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Bad White [126]
1 year ago
11

The mass of Jupiter is 300 times the mass of the earth. Jupiter orbits the sun with Jupiter = 11.9 yr in an orbit with Jupiter =

5.2'outh Suppose the earth could be moved to the distance of Jupiter and placed in a circular orbit around the sun. Which of the following describes the earth's new period? Match the words in the left column to the appropriate blanks in the sentences on the right. Reset Help The new period will be 1 yr. This can be explained by the fact that The new period will be between 1 yr and 11.9 yr. The new period will be 11.9 yr. The new period will be more than 11.9 yr. The new period of the earth would depend on its speed. It's impossible for a planet of earth's mass to orbit at the distance of Jupiter otherwise the earth and Jupiter would collide. according to the third law of Kepler the orbital period depends on the semimajor axis length but not on the mass of the planet. the mass of the earth is less than the mass of Jupiter.
Chemistry
1 answer:
kondaur [170]1 year ago
8 0

The orbital period is proportional to r^(3/2) and does not depend on the satellite's mass. Any object at Jupiter's position will have the same orbital period regardless of mass. The correct answer is 11.9 yr. <u>Option C.</u>

As the Earth rotates on its axis creating day and night, it travels around the Sun in an elliptical orbit taking about 365 1/4 days to complete. The Earth's rotation axis is tilted with respect to the orbital plane. This creates seasons. The elliptical nature of the Earth's orbit is due to the first forces pushing the Earth away from the Sun's disk.

The momentum of this throw being greater the Earth's orbit would have been more elliptical or it might have been completely ejected from the solar system forever. The Earth's orbit defines a two-dimensional plane called the Ecliptic. It takes about 365 days for the earth to revolve around the sun. After years of analysis, Kepler found that Mars' orbit was likely elliptical, with the Sun at one of his focal points of the ellipse. This led Kepler to discover that all planets orbit the Sun in elliptical orbits and that the Sun is at one of his two focal points.

Learn more about The mass here:-brainly.com/question/26150306

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Use the successive ionization energies for this unknown element to identify the family it belongs to.
NNADVOKAT [17]

Answer: Belongs to the group 2A

Explanation:

As you can see, the first two ionization energies are close and low, meaning that this element ionizates easily.

Not only loses easily the first electron, but the second too

To remove the third electron you requiered a huge amount of energy

Now, elements easily ionizable are the ones from group IA, group 2A and transition metals.

The last ones have mixed characteristics in matter of how many electrons you can remove from them, so they are not a family.

Now the question: group I or group II ?

The elements of group I have low  ionization energies  for the first electron but high energies for the second ones.

Being all that said, the unknown element belongs to the Group 2A

4 0
2 years ago
What is the independent variable?<br> (For science)
DiKsa [7]

Answer:

The independent variable is what you change in the experiment.

Explanation:

The independent determines the dependent variable.

6 0
3 years ago
An acid with molar mass 84.48 g/mol is titrated with 0.650 M KOH. What volume of KOH solution is needed to titrate 1.70 grams of
RSB [31]

Answer:

V=0.0310L=3.10mL

Explanation:

Hello.

In this case, since the acid is monoprotic and the KOH has one hydroxyl ion only, we can see that at the equivalence point the moles of both of them are the same:

n_{acid}=n_{KOH}

Thus, since we are given 1.70 g of the acid, we compute the moles of acid that were titrated:

n_{acid}=1.70g*\frac{1mol}{84.48g}=0.0201mol

Which equal the moles of KOH. In such a way, since the molarity is defined as moles over liters (M=n/V), the liters are moles over molarity (V=n/M), thus, the resulting volume is:

V=\frac{0.0201mol}{0.650mol/L}\\\\V=0.0310L=3.10mL

Best regards!

7 0
3 years ago
determine mass of water formed when 12.5 L NH3(at298K and 1.50atm) is reacted with 18.9L of O2 (at 323K and 1.1atm)
sasho [114]

The  mass  of water formed  is


<u><em>calculation</em></u>

Use  the  ideal   gas  equation   to  calculate the  moles of  NH3  and O2

that  is  Pv= n RT

where;  P= pressure,  

V=  volume,

n = number  of  moles,

R=gas   constant  = 0.0821  l .atm/ mol.K

make n the formula of  the subject  by diving   both side  by  RT

n =  PV /RT

The   moles of NH3

n= (1.50 atm  x 12.5 L) /(  0.0821 L. atm /mol.k   x 298 K)  =0.766  moles

The  moles  of  O2

=(1.1 atm  x 18.9  L) /  (  0.0821 L. atm/ mol.k   x 323 K) = 0.784  moles


write the reaction  between  NH3  and  O2

4 NH3  + 5 O2  →4 No  +6H2O


from  equation above  0.766  moles of NH3  reacted to produce  

0.766 x 6/4 =1.149 moles of H2O


0.784  moles of O2   reacted to  produce  0.784  x 6/5=0.9408  moles  of H20


since  O2  is totally  consumed, O2  is the limiting  reagent  and therefore  the  moles of H2O  produced=  0.9408  moles


mass  of  H2O  = moles x molar mass

 from  periodic table the  molar mass  of H2O  =  (1 x2)+16= 18  g/mol

mass = 18 g/mol  x 0.9408  moles= 16.93  grams


3 0
3 years ago
As of right now, which of the following forms of nuclear power is the most feasible for human use?
nikitadnepr [17]

As of now, the nuclear fission is the most feasible energy source for human use. All the nuclear power plants are based on the controlled nuclear fission reaction, where the unstable nucleus is bombarded with high speed neutrons, thus, splitting the nucleus into stable ones and releasing huge amount of energy. The nuclear fusion requires very high temperature, the temperature equal's to that of the sun. Hence, it is not feasible right now. As the technology advances, we will see advancement in other form of energies.

6 0
3 years ago
Read 2 more answers
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