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polet [3.4K]
3 years ago
11

The length of a tennis court is 10 feet shorter than 3 times its width x express and the perimeter of the tennis court in terms

x
Mathematics
1 answer:
Norma-Jean [14]3 years ago
4 0

First, let's define our variables.


Let's call our width X(given)

and our length, since it's 10 shorter than 3 times the width, we can call our length:

3x-10

So, the perimeter of a rectange is equal to 2 times the length + 2 times the width.


So, when we plug our values in, we get

2(3x-10)+2x\\6x-20+2x\\8x-20

The perimeter is 8x-20


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1. (5pt) In a recent New York City marathon, 25,221 men finished and 253 dropped out. Also,
gladu [14]

Answer:

(a) Explained below.

(b) The 99% confidence interval for the difference between proportions is (-0.00094, 0.00494).

Step-by-step explanation:

The information provided is:

n (Men who finished the marathon) = 25,221

n (Women who finished the marathon) = 12,883

Compute the proportion of men and women who finished the marathon as follows:

\hat p_{1}=\frac{25221}{25221 +253}=0.99\\\\\hat p_{2}=\frac{12883 }{12883+163}=0.988

The combined proportion is:

\hat P=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}\\\\=\frac{25221+12883}{38520}\\\\=0.989

(a)

The hypothesis is:

<em>H</em>₀: The rate of those who finish the marathon is the same for men and women, i.e. <em>p</em>₁ - <em>p</em>₂ = 0.

<em>Hₐ</em>: The rate of those who finish the marathon is not same for men and women, i.e. <em>p</em>₁ - <em>p</em>₂ ≠ 0.

Compute the test statistic as follows:

Z=\frac{\hat p_{1}-\hat p_{2}}{\sqrt{\hat P(1-\hat P)\cdot [\frac{1}{n_{1}}+\frac{1}{n_{2}}]}}

   =\frac{0.99-0.988}{\sqrt{0.989(1-0.989)\times[\frac{1}{25474}+\frac{1}{13046}]}}\\\\=1.78

Compute the <em>p</em>-value as follows:

p-value=2\times P(Z>1.78)\\\\=2\times 0.03754\\\\=0.07508\\\\\approx 0.075

The <em>p</em>-value of the test is more than the significance level. The null hypothesis was failed to be rejected.

Thus, concluding that the rate of those who finish is the same for men and women.

(b)

Compute the 99% confidence interval for the difference between proportions as follows:

The critical value of <em>z</em> for 99% confidence level is 2.58.

CI=(\hat p_{1}-\hat p_{2})\pm z_{\alpha/2}\cdot\sqrt{\frac{\hat p_{1}(1-\hat p_{1})}{n_{1}}+\frac{\hat p_{2}(1-\hat p_{2})}{n_{2}}}

     =(0.99-0.988)\pm 2.58\times\sqrt{\frac{0.99(1-0.99)}{25474}+\frac{0.988(1-0.988)}{13046}}\\\\=0.002\pm 0.00294\\\\=(-0.00094, 0.00494)\\\\

Thu, the 99% confidence interval for the difference between proportions is (-0.00094, 0.00494).

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Can anyone help me I was self isolating when my class was taught this and I can't get in contact with my teacher
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Answer:

Step-by-step explanation:

3x +2y = 13   -----------------(i)

x + 2y = 7    ----------------(ii)

Multiply the equation (ii) by (-1) and then add.

(i)              3x + 2y = 13

(ii)*(-1)      <u>-x    - 2y = -7 </u>        {Now, add and y will be eliminated}

                 2x       = 6

                        x = 6/2

x = 3

Plug in x = 3 in equation (i)

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