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3 years ago

Nine out of ten student prefer math class over lunch. How many students do not prefer math if 200 students were asked

2 answers:

8 0

If nine out of ten students prefer math class over lunch then that's 90%. Which means 10% of the 200 don't prefer it. 200/10= 20 people do not prefer math

Leya [2.2K]3 years ago

8 0

Answer:

20 students do NOT prefer math over lunch.

Step-by-step explanation:

Hello, great question. These types are questions are the beginning steps for learning more advanced Algebraic Equations.

If nine out of ten students ( $\frac{9}{10}$ ) prefer math class over lunch, then we can infer that one out of ten students ( $\frac{1}{10}$ ) do not.

$\frac{1}{10} = 0.10$ or 10%

As we can see, this equals a 10% of the students that were asked. If 200 students were asked, we would need to find what 10% of 200 would be. We can do this by multiplying 200 by the decimal form of 10% like so,

$200 * 0.10 = 20 students$

So we can see that 20 students do NOT prefer math over lunch.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

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2 years ago

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What are the possible rational roots of the polynomial equation? 0=2x7+3x5−9x2+6

RoseWind [281]

Answer: $\pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}$

Step-by-step explanation:

We can use the Rational Root Test.

Given a polynomial in the form:

$a_nx^n +a_{n- 1}x^{n - 1} + … + a_1x^1 + a_0 = 0$

Where:

- The coefficients are integers.

- $a_n$ is the leading coeffcient ( $a_n\neq 0$ )

- $a_0$ is the constant term $a_0\neq 0$

Every rational root of the polynomial is in the form:

$\frac{p}{q}=\frac{\pm(factors\ of\ a_0)}{\pm(factors\ of\ a_n)}$

For the case of the given polynomial:

$2x^7+3x^5-9x^2+6=0$

We can observe that:

- Its constant term is 6, with factors 1, 2 and 3.

- Its leading coefficient is 2, with factors 1 and 2.

Then, by Rational Roots Test we get the possible rational roots of this polynomial:

$\frac{p}{q}=\frac{\pm(1,2,3,6)}{\pm(1,2)}=\pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}$

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3 years ago

Dilate by a scale factor of 1/2 AL D

Firdavs [7]

Answer:

The image triangle ΔD'L'W' after the dilation by a scale factor of 1/2 will have the vertices:

D' (0, 1)

L' (1/2, 5/2) or L'(0.5, 2.5)

W' (5/2, 2) or W'(2.5, 2)

`The figure of the dilated image is attached below.

Step-by-step explanation:

Given the triangle ΔDLW withe the vertices

D(0, 2)

L(1, 5)

W(5, 4)

As the scale factor 1/2 < 0, thus the image triangle will be smaller than the original triangle.

The rule of dilation is given by

Dilation: (x, y) → (1/2x, 1/2y), centered at (0, 0)

D(0, 2) → D' (1/2x, 1/2y) → D' (1/2(0), 1/2(2)) = D' (0, 1)

L(1, 5) → L'(1/2x, 1/2y) → L'(1/2(1), 1/2(5)) = L' (1/2, 5/2)

W(5, 4) → W'(1/2x, 1/2y) → W'(1/2(5), 1/2(4)) = W' (5/2, 2)

Therefore, the image triangle ΔD'L'W' after the dilation by a scale factor of 1/2 will have the vertices:

D' (0, 1)

L' (1/2, 5/2) or L'(0.5, 2.5)

W' (5/2, 2) or W'(2.5, 2)

`The figure of the dilated image is attached below.

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