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klasskru [66]
3 years ago
7

Si tenemos un bloque de mármol que pesa 98 gramos, y lo introducimos en una probeta graduada que contiene 50 cm3 de agua; al cab

o de lo cual tenemos la lectura de 89 cm3 en el volumen del agua. ¿Cuál es el volumen y densidad del mármol?
Chemistry
1 answer:
Ber [7]3 years ago
3 0

Answer:

- V_{marmol}=39cm^3

- \rho=2.5\frac{g}{cm^3}

Explanation:

Hola,

En este caso, dado que el volumen del agua es 50 centímetros cúbicos y el volumen de la probeta con el bloque de mármol es 89 centímetros cúbicos, el volumen del mármol es:

V_{marmol}=89cm^3-50cm^3\\\\V_{marmol}=39cm^3

Ahora, la densidad la calculamos con la masa de mármol dividido por el volumen del mismo:

\rho =\frac{m_{marmol}}{V_{marmol}} =\frac{98g}{39cm^3} \\\\\rho=2.5\frac{g}{cm^3}

¡Saludos!

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