Answer:
172 g
Explanation:
Let's consider the reduction of Au³⁺ to Au.
Au³⁺(aq) + 3 e⁻ → Au(s)
In order to find the mass of gold produced, we will use the following relations.
- 1 min = 60 s
- 1 A = 1 C/s
- The charge of 1 mole of electrons is 96,468 C (Faraday's constant).
- 1 mole of Au is deposited when 3 moles of electrons circulate.
- The molar mass of Au is 196.97 g/mol.
The mass of gold produced when 15.1 A of current are passed through a gold solution for 31.0 min is:
Answer:
The answer to your question is Energy = 36.036 J
Explanation:
Data
mass of Copper = 39 g
ΔT = 24°C
C = 0.0385 J/g°C
Q = ?
To calculate the energy absorbed just substitute the values given in the specific heat formula.
Q = mCΔT
Substitution
Q = (39)(0.0385)(24)
Simplification
Q = 36.036 J
Answer:
136.36 mL
Explanation:
Here we have to use the dilution formula
From C1V1= C2V2
Where;
C1= initial concentration of the solution= 12.0 M
C2= final concentration of the solution= 2.20 M
V1 = initial volume of the solution= 25.0 ml
V2= final volume of the solution= ?????
Then recall;
C1V1=C2V2
V2 = C1V1/C2
Substituting values from the parameters given;
V2= 12.0 × 25.0 / 2.20
V2= 136.36 mL
Answer:
The answer to your question is
4C₇H₁₇ + 45 O₂ ⇒ 28 CO₂ + 34H₂O
Explanation:
Write the equation
C₇H₁₇ + O₂ ⇒ CO₂ + H₂O
Process
1.- Check if the equation is balanced
Reactants Element Products
7 C 1
17 H 2
2 O 3
As the number of reactants and products is different, we conclude that the reaction is unbalanced.
2.- Write a coefficient "7" to CO₂ and a coefficient of 17/2 to H₂O
C₇H₁₇ + O₂ ⇒ 7CO₂ + H₂O
Reactants Element Products
7 C 7
17 H 17
2 O 51/2
3.- Write a coefficient of 45/2 to the O₂, and multiply all the equation by 2.
4C₇H₁₇ + 45 O₂ ⇒ 28 CO₂ + 34H₂O
Reactants Element Products
28 C 28
68 H 68
90 O 90
Answer:
During separation of substances with different boiling points, fractional distillation is used.
During separation of substances in an eutectic mixture or azeotropic mixture, steam distillation is used.