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Andrews [41]
3 years ago
11

which type of bonding involves sharing valence electrons, but the valence electrons aren't confined to a specific region between

atoms and instead exist throughout the crystal structure of the material?
Chemistry
1 answer:
VashaNatasha [74]3 years ago
8 0

Answer:

metallic bonding

Explanation:

Metallic bonding is bonding where electrons exist as "sea of electrons" meaning they can go anywhere in the structure and are not localized in specific place like covalent bonds are sometimes.

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Neptunium-237 undergoes a series of α-particle and β-particle productions to end up as thallium-205. How many α particles and β
Fantom [35]
<h3>Answer:</h3>

8 alpha particles

4 beta particles

<h3>Explanation:</h3>

<u>We are given;</u>

  • Neptunium-237
  • Thallium-205
  • Neptunium-237 undergoes beta and alpha decay to form Thallium-205.

We are required to determine the number of beta and alpha particles produced to complete the decay series.

  • We need to know that when a radioisotope emits an alpha particle the mass number reduces by 4 while the atomic number decreases by 2.
  • When a beta particle is emitted the mass number of the radioisotope increases by 1 while the atomic number remains the same.

In this case;

Neptunium-237 has an atomic number 93, while,

Thallium-205 has an atomic number 81.

Therefore;

²³⁷₉₃Np → x⁴₂He + y⁰₋₁e + ²⁰⁵₈₁Ti

We can get x and y

237 = 4x + y(0) + 205

237-205 = 4x

4x = 32

 x = 8

On the other hand;

93 = 2x + (-y) + 81

but x = 8

93 = 16 -y + 81

y = 4

Therefore, the complete decay equation is;

²³⁷₉₃Np → 8⁴₂He + 4⁰₋₁e + ²⁰⁵₈₁Ti

Thus, Neptunium-237 emits 8 alpha particles and 4 beta particles to become Thallium-205.

5 0
3 years ago
NEED HELP ASAP!!! What is the density of each of the following gases at STP? Show your work.
BaLLatris [955]

Answer:

A. 1.63g/dm^3 (3 s.f.)

B. 0.833g/dm^3 (3 s.f.)

C. 1.92g/dm^3 (3 s.f.)

Explanation:

Please see attached picture for full solution.

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3 years ago
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