Empirical formula and Molecular formula:
Vanillin has the empirical formula C₈H₈O₃ and the molecular formula C₈H₈O₃, they both are same.
What is Vanillin?
- Vanillin has the chemical formula C₈H₈O₃ and is classified as an organic compound.
- It is an aldehyde that is phenolic. Ether, hydroxyl, and aldehyde are some of their functional groups.
- It is the key ingredient in vanilla bean extract.
C, H, and O are present in this compound,
Mass percent composition = Divide by their atomic mass
C = 63.15/12.0107 = 5.2578
H = 5.30/1.0079 = 5.2582
O = 31.55/16 = 1.9719
Thus, the ratio of
carbon : hydrogen : oxygen
5.257811784 : 5.258249499 : 1.97199825
division of all numbers by the smallest we get,
2.666235523 : 2.666457488 : 1
further dividing it by 3 we get,
7.998706568 : 7.999372463 : 3
thus the ratio becomes 8:8:3
Therefore, the empirical formula is C₈H₈O₃
Empirical formula mass = (12x8) + (1x8) + (16x3)
= 96 + 8 + 48
= 152
n = Molecular mass of Vanillin/ Empirical formula mass
= 152.15/152
= 1.0009
Since the n-value is near to 1 thus the molecular formula will also be the same.
Therefore the molecular formula = C₈H₈O₃
Note: Your question is incomplete, but most probably your full question was Vanillin the flavoring agent in vanilla has a mass percent composition of 63.15 per h ,31.55per o and 5.30%H. determine the empirical formula and molecular formula if molecular mass of vanillin is 152.15 g/mol
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