Question

Vanillin the flavoring agent in vanilla has a mass percent composition of 63.15 per h ,31.55per o. determine the empirical formula and molecular formula if molecular mass of vanillin is 152.15 g/mol

Answer 1

Empirical formula and Molecular formula:

Vanillin has the empirical formula C₈H₈O₃ and the molecular formula  C₈H₈O₃, they both are same.

What is Vanillin?

• Vanillin has the chemical formula C₈H₈O₃ and is classified as an organic compound.
• It is an aldehyde that is phenolic. Ether, hydroxyl, and aldehyde are some of their functional groups.
• It is the key ingredient in vanilla bean extract.

C, H, and O are present in this compound,

Mass percent composition = Divide by their atomic mass

C = 63.15/12.0107 = 5.2578

H = 5.30/1.0079 = 5.2582

O = 31.55/16 = 1.9719  

Thus, the ratio of

carbon         :   hydrogen        :  oxygen

5.257811784 : 5.258249499 : 1.97199825

division of all numbers by the smallest we get,

2.666235523 : 2.666457488 : 1

further dividing it by 3 we get,

7.998706568 : 7.999372463 : 3

thus the ratio becomes 8:8:3

Therefore, the empirical formula is C₈H₈O₃

Empirical formula mass = (12x8) + (1x8) + (16x3)

                                       = 96 + 8 + 48

                                       = 152

n = Molecular mass of Vanillin/ Empirical formula mass

  = 152.15/152

  = 1.0009  

Since the n-value is near to 1 thus the molecular formula will also be the same.

Therefore the molecular formula = C₈H₈O₃

Note: Your question is incomplete, but most probably your full question was Vanillin the flavoring agent in vanilla has a mass percent composition of 63.15 per h ,31.55per o and 5.30%H. determine the empirical formula and molecular formula if molecular mass of vanillin is 152.15 g/mol

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