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3 years ago

Calculate the velocity of an ocean wave that has a wavelength of 5 meters and a frequency of 2 Hertz (Hz).

Chemistry

2 answers:

bulgar [2K]3 years ago

4 0

Answer:

Option C. 10m/s

Explanation:

Data obtained from the question include:

Wavelength = 5m

Frequency = 2Hz

Velocity =..?

Velocity of a wave is related to the wavelength and frequency by the following equation:

Velocity = wavelength x frequency

With the above equation, we can easily calculate the velocity of the ocean wave as follow:

Velocity = 5 x 2

Velocity = 10m/s

From the calculation made above, we can see that the velocity of the ocean wave is 10m/s.

dangina [55]3 years ago

4 0

Answer:

10 m/s

Explanation:

Edge

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bekas [8.4K]

Answer:

Explanation:

Protein synthesis involves two major steps:

Transcription of the DNA to mRNA (a form of RNA)
Translation of the mRNA molecule into a protein.

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6 0

3 years ago

Read 2 more answers

the chloride of a metal M contains 47.25% of metal 1.0 gram of metal would be displaced from a compound by 0.88 gram of another

GenaCL600 [577]

Answer:

The equivalent weight of M is approximately 31.8 g

The equivalent weight of N is approximately 27.98 g

Explanation:

The given parameters are;

The percentage of the the metal M in in the chloride = 47.25%

Where by the chemical formula for the metal chloride is MClₓ, we have;

47.25% of the mass of MClₓ = Mass of M = W

Therefore, we have;

$\dfrac{0.4725}{W} = \dfrac{1}{W + 35.5 \cdot x}$

0.4725 × (W + 35.5·x) = W

0.4725·W + 0.4725×35.5×x = W

W - 0.4725·W = 16.77·x

0.5275·W = 16.77·x

W/x = 16.77/0.5275 = 31.799 = The equivalent weight of M

The equivalent weight of M = 31.799 ≈ 31.8 g

Given that 1 gram of M is displaced by 0.88 gram of N, then the equivalent weight of N that will displace 31.799 = 0.88 × 31.799 ≈ 27.98 g

The equivalent weight of N = 27.98 g.

7 0

3 years ago

In which example does entropy increase?

nikklg [1K]

Explanation:

Entropy -

In a system, the randomness is measured by the term entropy .

Randomness basically refers as a form of energy that can not be used for any work.

The change in entropy is given by amount heat per change in temperature.

entropy increases as the randomness increase ,

and ,

entropy decrease as the randomness decreases .

I. A piece of fruit freezes in liquid nitrogen.

randomness decreases , and so entropy decrease .

II. Librarians put library books back onto shelves at the end of the day.

randomness decreases , and so entropy decrease .

III. Liquid nitrogen boils in a beaker at room temperature.

change in state from less random liquid to gas , randomness increases , hence entropy increases

IV. Dry ice sublimes .

change in state from less random solid to gas , randomness increases , hence entropy increases .

V. A balloon collapses as its contents cool in liquid nitrogen .

cooling process , reduces the randomness , hence , entropy decreases .

5 0

4 years ago

Farmers who raise cotton once used arsenic acid, H₃AsO₄, as a defoliant at harvest time. Arsenic acid is a polyprotic acid with

Stels [109]

Explanation:

The reaction equation will be as follows.

$H_{3}AsO_{4} \rightleftharpoons H_{2}AsO^{-}_{4} + H^{+}$

Hence, the expression for $K_{a}$ is as follows.

$K_{a} = \frac{[H_{2}SO^{-}_{4}][H^{+}]}{[H_{3}AsO_{4}]}$

Let us assume that the concentration of both $[H_{2}AsO^{-}_{4}]$ and $[H^{+}]$ is x.

$2.5 \times 10^{-4} = \frac{x \times x}{0.5}$

x = 0.01118034

This means that the concentration of $[H^{+}]$ is 0.01118034.

Since, we know that the relation between pH and concentration of hydrogen ions is as follows.

pH = $-log [H^{+}]$

= $-log (0.01118034)$

= 1.958

Thus, we can conclude that the pH of a 0.500 M solution of arsenic acid is 1.958.

6 0

3 years ago

The balanced chemical equation for the reaction between sodium chloride and silver nitrate is:

bonufazy [111]

Answer:

We can Interprete it as 1mole of Sodium Chloride and 1mole of Silver Nitrate React to Produce

1Mole of Silver Chloride and 1Mole of Sodium Nitrate

7 0

3 years ago

Read 2 more answers