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2 years ago

Read the list of substances. Wood, Copper, Iron, Foam Which substances are good conductors of heat?

Chemistry

2 answers:

oee [108]2 years ago

6 0

Answer: Option (B) is the correct answer.

Explanation:

Good conductors are defined as the substance through which heat can effectively pass.

For example, copper, and iron are good conductors of heat and electricity.

Generally, metals are good conductors of heat as well as electricity.

On the other hand, bad conductors are the substances through which heat is unable to flow.

For example, glass, wood, foam etc are all bad conductors of heat as well as electricity.

Thus, we can conclude that out of the given options copper and iron are good conductors of heat.

Sauron [17]2 years ago

3 0

Answer: Option (B) is the correct answer.

Explanation:

Metals are the substances that have more number of electrons. Metals are good conductors of heat and electricity.

For example, iron, copper, zinc are all metals and good conductors of heat and electricity.

Whereas wood and foam are is a poor conductor of heat and electricity.

Thus, we can conclude that out of the given options copper and iron are good conductors of heat.

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The densities of gases a, b, and c at stp are 1.25 g/l, 2.86 g/l and 0.714 g/l, respectively. calculate the molar mass of each s

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The molar mass of a, b and c at STP is calculated as below

At STP T is always= 273 Kelvin and ,P= 1.0 atm

by use of ideal gas equation that is PV =nRT
n(number of moles) = mass/molar mass therefore replace n in the ideal gas equation

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multiply both side by molar mass and then divide by Pv to make molar mass the subject of the formula

that is molar mass = (mass x RT)/ PV

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therefore by replacing mass/volume in the equation by density the equation
molar mass=( density xRT)/P where R = 0.082 L.atm/mol.K

the molar mass for a
= (1.25 g/l x0.082 L.atm/mol.k x273k)/1.0atm = 28g/mol

the molar mass of b
=(2.86g/l x0.082L.atm/mol.k x273 k) /1.0 atm = 64 g/mol

the molar mass of c

=0.714g/l x0.082 L.atm/mol.K x273 K) 1.0atm= 16 g/mol

therefore the
gas a is nitrogen N2 since 14 x2= 28 g/mol
gas b =SO2 since 32 +(16x2)= 64g/mol
gas c = methaneCH4 since 12+(1x4) = 16 g/mol

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Therefore, reaction equation when an aluminum- nuclide transforms into a phosphorus- nuclide by absorbing an alpha particle and emitting a neutron is as follows.

$^{27}_{13}Al + ^{1}_{0}n \rightarrow ^{30}_{15}P + ^{1}_{0}n$

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Answer:

D = m/v.

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