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Rom4ik [11]
3 years ago
6

6&7 please...............

Mathematics
1 answer:
pychu [463]3 years ago
8 0
There the same so -37
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Find the point (x1,x2) that lies on the line x1 +5x2 =7 and on the line x1 - 2x2 = -2.
Savatey [412]

Given :

Two equation x_1 +5x_2 =7 and x_1 - 2x_2 = -2 .

To Find :

The point of intersection of these lines .

Solution :

We will use elimination method :

From equation 1 :

x_1=7-5x_2

Putting value of x_1 in equation 2 we get :

(7-5x_2)-2x_2=-2\\\\7-7x_2=-2\\\\x_2=\dfrac{9}{7}

Putting value of x_2 in equation 1 we get :

x_1+5\times \dfrac{9}{7}=7\\\\x_1=\dfrac{4}{7}

Therefore , point of interaction is (\dfrac{4}{7},\dfrac{9}{7}) .

Hence , this is the required solution .

7 0
3 years ago
Please help me, its urgent ❗❗❗❗❗❗❗❗❗❗❗❗
lorasvet [3.4K]

Answer:

the answer to this one is A.

Step-by-step explanation:

3 0
3 years ago
Write the decimal equivalent of the following: seven hundred seventy-five thousandths?
baherus [9]

Answer:

0.775

Step-by-step explanation:

think place values to the right

tenths, hundredths, thousandths

6 0
3 years ago
How do you do C and B
Hoochie [10]
"the argument" of a function, is simply "the expression being evaluated by that function".

\bf a)\qquad (x+2)^3\impliedby \stackrel{function}{(\qquad )^3}\qquad \stackrel{argument}{x+2}
\\\\\\
b)\qquad f(2x-1)\impliedby \stackrel{function}{f(\qquad )}\qquad \stackrel{argument}{2x-1}
\\\\\\
c)\qquad \sqrt{x^2+4}\qquad \stackrel{function}{\sqrt{\qquad }}\qquad \stackrel{argument}{x^2+4}
\\\\\\
d)\qquad sin(5x)\impliedby \stackrel{function}{sin(\qquad )}\qquad \stackrel{argument}{5x}
4 0
3 years ago
- If f ( x ) = x² + 2x - 1 and g ( x ) = 3x - 2 , then verify the following :
RideAnS [48]

Step-by-step explanation:

Hey there!

Given;

f ( x ) = x² + 2x - 1

g ( x ) = 3x - 2

To verify:

( \frac{f}{g} )(2) =  \frac{f(2)}{g(2)}

LHS:

(\frac{f}{g} )(x) =  \frac{ {x}^{2}  + 2x - 1}{3x - 2}

~ Insert "2" instead of "x".

(\frac{f}{g} )(2) =  \frac{ {2}^{2} + 2 \times 2 - 1 }{3 \times 2 - 2}

Simplify it;

\frac{f}{g} (2) =  \frac{4 + 4 - 1}{6 - 2}

Therefore; (f/g)(2) = 7/4.

RHS:

\frac{f(x)}{g(x)}  =  \frac{ {x}^{2}  + 2x - 1}{3x - 2}

~Insert "2" instead of"x".

\frac{f(2)}{g(2)}  =  \frac{ {2}^{2} + 2 \times 2 - 1 }{3 \times 2 - 2}

Simplify it.

\frac{f(2)}{g(2)}  =  \frac{4 + 4 - 1}{6 - 2}

Therefore, f(2)/g(2) = 7/4.

Since (f/g)(2) = f(2)/g(2) = 7/4.

<em><u>Proved!</u></em>

<u>Hope </u><u>it </u><u>helps</u><u>!</u>

3 0
3 years ago
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