If velocity is positive, which would most likely yield a negative acceleration?
1 answer:
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Answer:
Given that
P = RT/V + a/V²
We know that
H= U + PV
For T= Constant (ΔU=0)
ΔH= ΔU +Δ( PV)
ΔH= Δ( PV)
P = RT/V + a/V²
P V= RT + a/V
dH/dV = d(RT + a/V)/dV
dH/dV = - a/V²
So the expression of dH/dV
b)
In isothermal process
(ΔU=0)
Now by putting the all values
ΔH = 17.06 L.atm