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BlackZzzverrR [31]
3 years ago
14

You travel 60 meters to the left in 20 seconds and then you travel 60 meters to the right in 30 seconds; what is your average ve

locity?
What is the answer and what are the steps to arrive at the answer? I need help figuring this out.
Physics
1 answer:
vovikov84 [41]3 years ago
4 0
Average velocity = displacement / time

In this case, since you move left 60, then right 60, you return to the starting point making the displacement zero.

average velocity = 0 / 60 sec = zero

the average speed is calculated using total distance traveled.

average speed = distance / time

average speed = 120 meters / 60 sec = 2 m/s
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the weatherman reports the storm waves are about 2 meters high and 35 meters apart. What properties of waves is the reporter des
8_murik_8 [283]

Answer:

Amplitude and wavelength

Explanation:

- The amplitude of a wave is the maximum displacement of the wave, measured with respect to the equilibrium position (so, for a water wave it is the maximum height of the wave relative to the equilibrium position)

- The wavelength of a wave is the distance between two consecutive crests (or throughs) of a wave. So, for a water wave, it is the distance between two consecutive waves

Therefore, in the example in the problem we have:

- 2 meters corresponds to the amplitude

- 35 meters corresponds to the wavelength

6 0
3 years ago
The maximum current output of a 60 ω circuit is 11 A. What is the root mean square voltage of the circuit?
goldenfox [79]

Answer:

660V

Explanation:

V=IR

V=?, I=11A,R=60w

V=60 ×11

=660V

8 0
3 years ago
What percentage of the earth's surface is covered in water
Alla [95]

Answer:

71 % of the earth's surface is covered in water

8 0
3 years ago
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Anton [14]
Potential and kinetic
6 0
3 years ago
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If the light wave has a wavelength of 10m what would be its velocity
s2008m [1.1K]

If this case could ever happen, the speed would follow from this formula:

v = f \cdot \lambda

with f the frequency and lambda the wavelength. We are give a wavelength of 10m. The frequencies of the visible light can range between 400 to about 790 Terahertz, so let us pick a middle point of 600 THz ("green-ish") as a "representative."

v = 600THz\cdot 10m = 6\cdot 10^{14} \frac{1}{s}\cdot 10 m = 6\cdot10^{15}\frac{m}{s}

The speed of such a wave would have to be 6e+15 m/s (which would be 7 orders of magnitude higher than the universal speed of light constant)

7 0
3 years ago
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