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ycow [4]
4 years ago
13

The driving force for fluid flow is the pressure difference, and a pump operates by raising the pressure of a fluid (by converti

ng the mechanical shaft work to flow energy). A gasoline pump is measured to consume 3.8 kW of electric power when operating. If the pressure differential between the outlet and inlet of the pump is measured to be 7 kPa and the changes in velocity and elevation are negligible, determine the maximum possible volume flow rate of gasoline.
Engineering
1 answer:
Lady_Fox [76]4 years ago
3 0

Answer:

The maximum possible volume flow of gasoline is 0.543 m^3/s

Explanation:

Power = pressure differential × volume flow rate

Power = 3.8 kW

Pressure differential = 7 kPa

Volume flow rate = power ÷ pressure differential = 3.8 ÷ 7 = 0.543 m^3/s

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