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ycow [4]
4 years ago
13

The driving force for fluid flow is the pressure difference, and a pump operates by raising the pressure of a fluid (by converti

ng the mechanical shaft work to flow energy). A gasoline pump is measured to consume 3.8 kW of electric power when operating. If the pressure differential between the outlet and inlet of the pump is measured to be 7 kPa and the changes in velocity and elevation are negligible, determine the maximum possible volume flow rate of gasoline.
Engineering
1 answer:
Lady_Fox [76]4 years ago
3 0

Answer:

The maximum possible volume flow of gasoline is 0.543 m^3/s

Explanation:

Power = pressure differential × volume flow rate

Power = 3.8 kW

Pressure differential = 7 kPa

Volume flow rate = power ÷ pressure differential = 3.8 ÷ 7 = 0.543 m^3/s

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An uncovered swimming pool loses 1.0 inch of water off its 1,000 ft^2 surface each week due to evaporation. The heat of vaporiza
soldi70 [24.7K]

Answer:

The affirmation is true, the cover will be worth buying

Explanation:

The equation necessary to use is

E = m*cv,

Where

cv: the heat of vaporization.  

Finding the rate at which the water evaporates (m^3/week).  

The swimming pool loses water at 1 inch/week off its 1,000 ft^2

Than,

1000 ft² * 1 in/wk * 1 ft/12 in = 83.33 ft³/week

To obtains the rate of mass loss it is necessary to multiply it for the density of water

83.33 ft³/week * 62.4 lb/ft³ = 5200 lb/week

Knowing the vaporization heat it is possible to find the rate of heat which is leaving the swimming pool  

5200 lb/week * 1050 BTU/lb = 5460000 btu/week

Over a 15-week period, the pool loses 81.9 million BTU.  

Knowing the cost of energy to heat the pool is $10.00 per million btu

The price = $819

This way, the affirmation is true, the cover will be worth buying

3 0
3 years ago
g . 3. For each of the following statements Write the statement as an English sentence that does not use the symbols for quan 2.
lubasha [3.4K]

Answer:

(a)

( ∃x ∈ Q) ( x > √2)

There exists a rational number x such that x > √2.

( ∀x ∈ Q) ( ( x ≤ √2)

For each rational number x,  x ≤ √2.

(b)

(∀x ∈ Q)(x² -  2 ≠ 0).

For all rational numbers x, x² -  2 ≠ 0

( ∃x ∈ Q ) ( x² - 2 = 0 )

There exists a rational number x such that  x² -  2 = 0

(c)

(∀x ∈ Z)(x is even or x is odd).

For each integer x, x is even or x is odd.

( ∃x ∈ Z ) (x is odd and x is even)

There exists an integer x such that x is odd and x is even.

(d)

( ∃x ∈ Q) ( √2 < x < √3 )

There exists a rational number x such that √2 < x < √3

(∀x ∈ Q) ( x ≤ √2 or x ≥ √3 )

For all rational numbers x,  x ≤ √2 or x ≥ √3.

3 0
3 years ago
Steam enters an adiabatic turbine at 800 psia and9008F and leaves at a pressure of 40 psia. Determine themaximum amount of work
Naily [24]

Answer:

w_{out}=319.1\frac{BTU}{lbm}

Explanation:

Hello,

In this case, for the inlet stream, from the steam table, the specific enthalpy and entropy are:

h_1=1456.0\frac{BTU}{lbm} \ \ \ s_1=1.6413\frac{BTU}{lbm*R}

Next, for the liquid-vapor mixture at the outlet stream we need to compute its quality by taking into account that since the turbine is adiabatic, the entropy remains the same:

s_2=s_1

Thus, the liquid and liquid-vapor entropies are included to compute the quality:

x_2=\frac{s_2-s_f}{s_{fg}}=\frac{1.6313-0.39213}{1.28448}=0.965

Next, we compute the outlet enthalpy by considering the liquid and liquid-vapor enthalpies:

h_2=h_f+x_2h_f_g=236.14+0.965*933.69=1136.9\frac{BTU}{lbm}

Then, by using the first law of thermodynamics, the maximum specific work is computed via:

h_1=w_{out}+h_2\\\\w_{out}=h_1-h_2=1456.0\frac{BTU}{lbm}-1136.9\frac{BTU}{lbm}\\\\w_{out}=319.1\frac{BTU}{lbm}

Best regards.

3 0
3 years ago
A disk is rotating around an axis located at its center. The angular velocity is 0.5 rad/s. The radius of the disk is 0.4 m. Wha
dimaraw [331]

Answer:

0.2 m/s

Explanation:

The velocity of a point on the edge of a disk rotating disk can be calculated as:

v=\omega*r

Where \omega is the angular velocity and r the radius of the disk. This leads to:

v=0.5\,rad/s\,*\,0.4\,m=0.2\,m/s

4 0
4 years ago
Read 2 more answers
4. Three routes connect an origin and a destination with performance functions tl = 8 + 0.5x1, t2 = 1 + 2x2, and t3 = 3 + 0.75x3
Helga [31]

Answer:

X1 = 2081.64

X2 = 523.91

X3 = 1394.45

Explanation:

See the attached pictures for detailed explanation.

3 0
3 years ago
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