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Dima020 [189]
3 years ago
7

Most sodium atoms have an atomic mass of 23, but a few have atomic

Physics
1 answer:
irina1246 [14]3 years ago
8 0

Answer:

c

Explanation:

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a car dealer sells 4 makes of cars in 5 colors with either standard or automatic transmissions. how many variations does the dea
Anuta_ua [19.1K]

<u>The number of variations the dealership have is 40 cars</u>.

Data given;

  • The number of different product = 4
  • The number of transmission = 2 (standard or automatic)
  • The numbers of colors available = 5

<h3>Dealership variation </h3>

This is the total numbers of cars available in the dealer shop at the moment.

To get that, we simply multiply the numbers of colors available, the number of transmission and the makes of car available.

This is equal to

4*2*5=40

From the above calculation, we can say that <u>the variations the dealership offers is 40</u>

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7 0
3 years ago
A car is a compound machine true or false
Viktor [21]
True is the answer. I believe
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3 years ago
How high would a projectile go if it was launched from ground level with an initial speed of 26 m/s at an angle of 30 degrees ab
tigry1 [53]

Answer:

Vy = 26 m/s sin 30 = 13 m/s      vertical speed

t = Vy / a = 13 m/s / 9.80 m/s^2 = 1.33 sec     time to reach Vy = 0

H = Vy t + 1/2 g t^2

H = 13 m/s * 1.33 sec - 1.33^2 * 9.8 / 2 m = 8.62 m

4 0
1 year ago
What is another name for constructive interference?
SOVA2 [1]
C I hope this help bud
4 0
3 years ago
New attempt is in progress. Some of the new entries may impact the last attempt grading. Incorrect. The hammer throw is a track-
Morgarella [4.7K]

This question involves the concepts of centripetal force, range of projectile and projectile motion.

The magnitude of centripetal force is "2812.8 N".

First, we will find the velocity of the ball by using the formula of the range of the projectile.

R = \frac{v^2Sin2\theta}{g}

where,

R = range of projectile = 86.75 m

v = speed = ?

θ = launch angle = 47.9°

g = acceleration due to gravity = 9.81 m/s²

Therefore,

86.75\ m = \frac{(v)^2Sin(2)(47.9^o)}{9.81\ m/s^2}\\\\v = \sqrt{\frac{(86.75\ m)(9.81\ m/s^2)}{Sin95.8^o}}

v = 29.25 m/s

Now, we will use the formula to find out the centripetal force:

F_c = \frac{mv^2}{r}

where,

F_c = Centripetal Force = ?

m = mass of the ball = 7.3 kg

v = speed = 29.25 m/s

r = radius = 2.22 m

Therefore,

F_c = \frac{(7.3\ kg)(29.25\ m/s)^2}{2.22\ m}

<u>Fc = 2812.8 N = 2.812 KN</u>

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