Question

What is the pendulum length whose period is 2.0s ?

Answer 1

$Formula\ for\ period:\\\ T=2 \pi \sqrt{\frac{L}{g}}\\\ g-gravity=9,8 \frac{m}{s^2} ,\ L-pendulum \ length \\\\ \frac{T}{2 \pi } = \sqrt{ \frac{L}{g} }|square\\\\ \frac{T^2}{2 \pi } = \frac{L}{g} \\\\\ \frac{T^2}{2 \pi }*g=L\\\\ L= \frac{2^2}{2*3,14 }*9,8= \frac{39,2}{6,28} =6,24m$$T=2 \pi \sqrt{\frac{L}{g}} \\ \frac{T}{2 \pi } = \sqrt{ \frac{L}{g} }|square\\ \frac{T^2}{2 \pi } = \frac{L}{g} \\ \frac{T^2}{2 \pi }*g=L\\ L= \frac{2^2}{2*3,14 }*9,8= \frac{39,2}{6,28} =6,24m$