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Otrada [13]
3 years ago
15

What is the earths energy budget? A. The balance between the amount of energy coming into earth from the sun and going back out

into space B. The total energy available in the universe minus earths energy use C. The total energy output by the sun minus all the solar system plants energy use D. The total energy output by the sun plus the energy reflected by earths atmosphere back into space
Physics
2 answers:
OlgaM077 [116]3 years ago
7 0
Our Earth budget is how much energy we receive from the sun.
So the best answer is A
myrzilka [38]3 years ago
5 0
<h3 />

A. The balance between the amount of energy coming into earth from the sun and going back out into space

<h3 />
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If a woman weighs 125 lb, her mass expressed in kilograms is x kg, where x is
adelina 88 [10]
The first thing you should know to solve this problem is the conversion of pounds to kilograms:
 1lb = 0.45 Kg
 We can solve this problem by a simple rule of three
 1lb ---> 0.45Kg
 125lb ---> x
 Clearing x we have:
 x = ((125) / (1)) * (0.45) = 56.25 Kg.
 Answer
 her mass expressed in kilograms is 56.25 Kg.
3 0
3 years ago
Read 2 more answers
This force can either push the block upward at a constant velocity or allow it to slide downward at a constant velocity. The mag
Dmitry [639]

Answer:

Part a)

F = 135.7 N

Part b)

F = 62.5 N

Explanation:

Part a)

If block is sliding up then net force must be zero and friction will be in opposite to the direction of motion of the block

Fcos\theta = mg + F_f

Fsin\theta = F_n

so we have

Fcos\theta = mg + \mu(Fsin\theta)

F(cos\theta - \mu sin\theta) = mg

F = \frac{mg}{cos\theta - \mu sin\theta}

F = \frac{55}{cos50 - 0.310(sin50)}

F = 135.7 N

Part b)

If block is sliding down then net force must be zero and friction will be in opposite to the direction of motion of the block

Fcos\theta = mg - F_f

Fsin\theta = F_n

so we have

Fcos\theta = mg - \mu(Fsin\theta)

F(cos\theta + \mu sin\theta) = mg

F = \frac{mg}{cos\theta + \mu sin\theta}

F = \frac{55}{cos50 + 0.310(sin50)}

F = 62.5 N

6 0
3 years ago
If the crate shown here is moving at a constant speed in a straight line and the force applied is 310 N, what is the magnitude o
larisa86 [58]

Answer:

f_k = 310N

the answer is A.

Explanation:

Using the laws of newton:

∑F = ma

where ∑F is the sumatory of forces acting in the system, m the mass and a the acelertion of the system.

Then, if the block is moving with constant velocity, its aceleration is equal to 0, so:

∑F = m(0)

∑F = 0

It means that:

F -f_k = 0

where F is the force applied and f_k is the friction force. Replacing the value of F, we get:

310N -f_k = 0

Finally, solving for f_k:

f_k = 310N

8 0
3 years ago
Design a solution that can monitor and minimize the melting of sea ice caused by human activity
dedylja [7]

Answer:

CO2 emissions from fossil fuel burning should be minimized at all cost. The CO2 are gotten when the carbons from hydrocarbons react with air(oxygen). This gas erodes the ozone layer which makes the melting of ice caps faster due to increased amount of heat radiations on the earth. This is the only best and permanent solution to the reduction of the amount of heat rays on the earth which is a global problem.

Objects which reflects back the sunrays could also be inserted into the sea to prevent the melting of the ice caps.

7 0
3 years ago
Why forces are balanced and unbalanced? need help with this the lesson is tommorow
Naya [18.7K]
"Balanced" means that if there's something pulling one way, then there's also
something else pulling the other way. 

-- If there's a kid sitting on one end of a see-saw, and another one with the
same weight sitting on the other end, then the see-saw is balanced, and
neither end goes up or down.  It's just as if there's nobody sitting on it.

-- If there's a tug-of-war going on, and there are 300 freshmen pulling on one
end of a rope, and another 300 freshmen pulling in the opposite direction on
the other end of the rope, then the hanky hanging from the middle of the rope
doesn't move.  The pulls on the rope are balanced, and it's just as if nobody
is pulling on it at all.

-- If a lady in the supermarket is pushing her shopping cart up the aisle, and her
two little kids are in front of the cart pushing it in the other direction, backwards,
toward her.  If the kids are strong enough, then the forces on the cart can be
balanced. Then the cart doesn't move at all, and it's just as if nobody is pushing
on it at all.

From these examples, you can see a few things:

-- There's no such thing as "a balanced force" or "an unbalanced force".
It's a <em><u>group</u> of forces</em> that is either balanced or unbalanced.

-- The group of forces is balanced if their strengths and directions are
just right so that each force is canceled out by one or more of the others.

-- When the group of forces on an object is balanced, then the effect on the
object is just as if there were no force on it at all.
4 0
3 years ago
Read 2 more answers
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