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Otrada [13]
3 years ago
15

What is the earths energy budget? A. The balance between the amount of energy coming into earth from the sun and going back out

into space B. The total energy available in the universe minus earths energy use C. The total energy output by the sun minus all the solar system plants energy use D. The total energy output by the sun plus the energy reflected by earths atmosphere back into space
Physics
2 answers:
OlgaM077 [116]3 years ago
7 0
Our Earth budget is how much energy we receive from the sun.
So the best answer is A
myrzilka [38]3 years ago
5 0
<h3 />

A. The balance between the amount of energy coming into earth from the sun and going back out into space

<h3 />
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Are you aware of human rights violations happening in your community? Explain.​
MA_775_DIABLO [31]

Answer:

Answer: We should be aware of human rights violation happening in our community. In our community, there are so many people who cannot practice their own religion and rituals. ... In many nations around the globe, domestic violence is another disadvantage in our society and another example of "human rights violations".

Explanation:

hope this helps u!!!!

3 0
4 years ago
A pressure cooker cooks a lot faster than an ordinary pan by maintaining a higher pressure and temperature inside. the lid of a
BlackZzzverrR [31]

Answer:

m=40.816\ gm

Explanation:

Given;

The operational pressure of the cooker, P=10^5\ Pa (gauge)

area of the opening, a=4\ mm^2

  • We know that the gauge pressure is measured with respect to the atmospheric pressure. As the atmospheric pressure acts on all the components of the system being observed so, we only need to counter the gauge pressure.

As the petcock sits on the opening of the cross-section so, it balances the built-in pressure due to its weight.

<u>Hence:</u>

m.g=P\times a

where:

m= mass of the petcock

g= acceleration due to gravity

m\times 9.8=10^5\times 4\times 10^{-6}

m=40.816\ gm

6 0
3 years ago
In class we calculated the range of a projectile launched on flat ground. Consider instead, a projectile is launched down-slope
zysi [14]

Answer:

With an initial speed of 10m/s at an angle 30° below the horizontal, and a height of 8m, the projectile travels 7.49m horizontally before it lands.

Explanation:

Since the horizontal motion is independent from the vertical motion, we can consider them separated. The horizonal motion has a constant speed, because there is no external forces in the horizontal axis. On the other hand, the vertical motion actually is affected by the gravitational force, so the projectile will be accelerated down with a magnitude g.

If we have the initial velocity v_o and its angle \theta, we can obtain the vertical component of the velocity v_{oy} using trigonometry:

v_{oy}=v_osin\theta

Therefore, if we know the height at which the projectile was launched, we can obtain the final velocity using the formula:

v_{fy}^{2} =v_{oy}^{2}+2gy\\\\ v_{fy}=\sqrt{v_{oy}^{2}+2gy }

Next, we compute the time the projectile lasts to reach the ground using the definition of acceleration:

g=\frac{v_{fy}-v_{oy}}{\Delta t} \\\\\Delta t= \frac{v_{fy}-v_{oy}}{g}=\frac{\sqrt{v_{oy}^{2}+2gy} -v_{oy}}{g}

Finally, from the equation of horizontal motion with constant speed, we have that:

x=v_{ox}\Delta t= v_{ox}\frac{\sqrt{v_{oy}^{2}+2gy} -v_{oy}}{g}

For example, if the projectile is launched at an angle 30° below the horizontal with an initial speed of 10m/s and a height 8m, we compute:

v_{ox}=10\frac{m}{s} cos30=8.66\frac{m}{s}\\v_{oy}=10\frac{m}{s} sin30=5\frac{m}{s}\\\\x=8.66\frac{m}{s} \frac{\sqrt{(5\frac{m}{s}) ^{2}+2(9.8\frac{m}{s^{2}})8m}-5\frac{m}{s}  }{9.8\frac{m}{s^{2} } } =7.49m

In words, the projectile travels 7.49m horizontally before it lands.

8 0
4 years ago
Describe a ball's motion as it rolls up a slanted
emmasim [6.3K]

The ball will decelerate as it moves upwards.

The magnitude of the ball's acceleration is 0.3 m/s² and it directed backwards.

The given parameters;

  • initial velocity of the ball, u = 1.25 m/s
  • time of motion of the ball, t = 4.22 s

As the ball rolls up the inclined plane, the velocity decreases and eventually becomes zero when the ball reaches the highest point of the plane.

Thus, the ball decelerate as it moves upwards.

The acceleration of the ball is calculate as;

a = \frac{v_f -v_0}{t} \\\\

<em>at the highest point on the incline plane, the final velocity </em>v_f<em> is zero</em>

a = \frac{0-1.25}{4.22} \\\\a = -0.3 \ m/s^2

Thus, the magnitude of the ball's acceleration is 0.3 m/s² and it directed backwards.

Learn more here:brainly.com/question/23860763

4 0
3 years ago
What is the period of a simple pendulum is its frequency is 20 Hz?
JulijaS [17]

Period  =  (1) / (frequency)

             =  (1) / (20/sec)

             =        1/20 sec 
5 0
4 years ago
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