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mars1129 [50]
4 years ago
12

There are 685 Students 80 Percent of them are going on a feild trip how many students are going on the feild trip

Mathematics
2 answers:
marin [14]4 years ago
6 0
685 students X 0.80 = 548 students going on the field trip.
Lelu [443]4 years ago
6 0
548 because if you take away 80% from the total number and add till you get yuore total thst is youre answer 137+548
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Step-by-step explanation:

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3 years ago
The product of x and 6 is less than or equal to -17.
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The answer is:
6x < -17
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4 years ago
For the following linear system, put the augmented coefficient matrix into reduced row-echelon form.
Anni [7]

Answer:

The reduced row-echelon form of the linear system is \left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]

Step-by-step explanation:

We will solve the original system of linear equations by performing a sequence of the following elementary row operations on the augmented matrix:

  1. Interchange two rows
  2. Multiply one row by a nonzero number
  3. Add a multiple of one row to a different row

To find the reduced row-echelon form of this augmented matrix

\left[\begin{array}{cccc}2&3&-1&14\\1&2&1&4\\5&9&2&7\end{array}\right]

You need to follow these steps:

  • Divide row 1 by 2 \left(R_1=\frac{R_1}{2}\right)

\left[\begin{array}{cccc}1&3/2&-1/2&7\\1&2&1&4\\5&9&2&7\end{array}\right]

  • Subtract row 1 from row 2 \left(R_2=R_2-R_1\right)

\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\5&9&2&7\end{array}\right]

  • Subtract row 1 multiplied by 5 from row 3 \left(R_3=R_3-\left(5\right)R_1\right)

\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]

  • Subtract row 2 multiplied by 3 from row 1 \left(R_1=R_1-\left(3\right)R_2\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]

  • Subtract row 2 multiplied by 3 from row 3 \left(R_3=R_3-\left(3\right)R_2\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&0&0&-19\end{array}\right]

  • Multiply row 2 by 2 \left(R_2=\left(2\right)R_2\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&-19\end{array}\right]

  • Divide row 3 by −19 \left(R_3=\frac{R_3}{-19}\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&1\end{array}\right]

  • Subtract row 3 multiplied by 16 from row 1 \left(R_1=R_1-\left(16\right)R_3\right)

\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&-6\\0&0&0&1\end{array}\right]

  • Add row 3 multiplied by 6 to row 2 \left(R_2=R_2+\left(6\right)R_3\right)

\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]

8 0
3 years ago
Find the length of side
quester [9]

Answer:

2*√2

Step-by-step explanation:

You need to use the trigonometrical function of angle (You should use the side sqrt2 and x to find the x). Take any acute angle (for example, 60 degrees)

The cos of this angle is equal to the ratio of adjoined leg (sqrt2) to the hypotenude (the side opposite to right angle, it is x)

cos60degrees= sqrt2/ x

1/2= sqrt2/x

x= 2*sqrt2= 2*√2

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3 years ago
During a business trip, an individual stopped at two rest stops. In the parking lot of the first rest stop, they counted 20 cars
olganol [36]

Answer

given,

on first stop

number of car = 20  and number of trucks = 18

on second stop

number of car = 18  and number of trucks = 10

we need to calculate which rest stop has higher ratio of car to truck.

Rest Stop 1

ratio= r₁ =\dfrac{cars}{trucks}

           r₁ =\dfrac{20}{18}

           r₁ =\dfrac{10}{9}

Rest Stop 2

ratio= r₂ =\dfrac{cars}{trucks}

           r₂ =\dfrac{18}{10}

           r₂=\dfrac{9}{5}

hence, r₂ > r₁

rest stop 2 has more car to truck ratio than rest stop 1

3 0
3 years ago
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