1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Akimi4 [234]
3 years ago
7

When a weather map shows a wind symbol at 270 it indicates that the wind is coming from the?

Physics
1 answer:
Montano1993 [528]3 years ago
5 0
For the answer to the question above, <span>When a weather map shows a wind symbol at 270 it indicates that the wind is coming from the WEST.
I hope my answer helped you. Feel free to ask more questions. Have a nice day!</span>
You might be interested in
A 37 N block rests on a horizontal surface. The coefficients of static and kinetic friction between the surface and the block ar
Ne4ueva [31]

Answer:

The frictional force acting on the block is 14.8 N.

Explanation:

Given that,

Weight of block = 37 N

Coefficients of static = 0.8

Kinetic friction = 0.4

Tension = 24 N

We need to calculate the maximum friction force

Using formula of friction force

f=\mu mg

Put the value into the formula

f=0.8\times37

f=29.6\ N

So, the tension must exceeds 29.6 N for the block to move

We need to calculate the frictional force acting on the block

Using formula of frictional force

f = \mu N

Put the value in to the formula

f=0.4\times37

f=14.8\ N

Hence, The frictional force acting on the block is 14.8 N.

6 0
3 years ago
This questic concerns a tablet that
Vanyuwa [196]

Answer:

The remaining percentage of drug concentration is about 88.7% 2 years after manufacture.

Explanation:

Recall the formula for the decay of a substance at an initial N_0 concentration at manufacture:

N(t)=N_0\,e^{-k\,\,t}

where k is the decay rate (in our case 0.06/year), and t is the elapsed time in years. Therefore, after 2 years since manufacture we have:

N=N_0\,e^{-0.06\,\,(2)}\\N=N_0\,e^{-0.12}\\N/N_0=e^{-0.12}\\N/N_0=0.8869

This in percent form is 88.7 %. That is, the remaining percentage of drug concentration is about 88.7% 2 years after manufacture.

3 0
3 years ago
Rita is a salon owner. She notices that her salon charged one of her clients, Linda, extra for a service that the clent did not
Aloiza [94]

Answer:

C hope it helps

call the client and inform her that she was incorrectly charged.

7 0
2 years ago
A red rubber ball rolls down a hill from rest with an acceleration of 7.8 m/s 2 . How fast is it moving after it has traveled 5
masya89 [10]

Answer:

39 m/s

Explanation:

7 0
2 years ago
PLEASE ANSWER, I NEED HELP
Scorpion4ik [409]

1) The gravitational force between Ellen and the moon is 1.56\cdot 10^{-3} N

2) The two forces are equal, while the acceleration of the bus is smaller than the acceleration of the bicycle.

Explanation:

1)

The magnitude of the gravitational force between two objects is given by

F=G\frac{m_1 m_2}{r^2}

where

G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2} is the gravitational constant

m_1, m_2 are the masses of the two objects

r is the separation between them

In this problem, we have:

m_1 = 47 kg is the mass of Ellen

m_2 = 7.35\cdot 10^{22} kg is the mass of the moon

r=3.84\cdot 10^8 m is the distance between Ellen and the moon

Substituting, we find the gravitational force between Ellen and the moon:

F=(6.67\cdot 10^{-11})\frac{(47)(7.35\cdot 10^{22})}{(3.84\cdot 10^8)^2}=1.56\cdot 10^{-3} N

2)

We can analyze the forces acting in the collision between the bus and the bicycle by using Newton's third law of motion, which states that:

"When an object A exerts a force (called action) on an object B, then object B exerts an equal and opposite force (called reaction) on object A"

Applied to our problem, this means that the force exerted by the bus on the bicycle during the collision (action force) is equal (and opposite) to the force exerted by the bicycle on the bus (reaction force).

Now let's analyze the accelerations of the two vehicles. We can find the acceleration of each vehicle by using Newton's second law:

a=\frac{F}{m}

where

a is the acceleration

F is the force exerted on the vehicle

m is the mass of the vehicle

As we said previously, the force F exerted on each of the two vehicles: so, the acceleration only depends on the mass. In particular, the acceleration is inversely proportional to the mass: therefore, the larger the mass of the vehicle, the smaller the acceleration. This means that the acceleration of the bus is smaller than the acceleration of the bicycle.

Learn more about gravitational force:

brainly.com/question/1724648

brainly.com/question/12785992

And about Newton's third law:

brainly.com/question/11411375

#LearnwithBrainly

6 0
3 years ago
Other questions:
  • A 50.0 kg child stands at the rim of a merry-go-round of radius 1.95 m, rotating with an angular speed of 2.80 rad/s.
    12·1 answer
  • Explain how a covalent compound can be a strong electrolyte and give an example.
    7·1 answer
  • A pelican flying along a horizontal path drops a fish from a height of 4.7 m. The fish travels 9.3 m horizontally before it hits
    9·1 answer
  • Imagine you are studying the turgor pressure at two different ends of a sieve tube. One end of the sieve tube is located within
    14·1 answer
  • A toy of mass 0.170-kg is undergoing SHM on the end of a horizontal spring with force constant k = 250 N/m . When the toy is a d
    12·1 answer
  • Not sure on this I know it’s not D please help
    7·1 answer
  • as you go above earths surface, the acceleration due to gravity will decrease. find the height, i meters, above the earths surfa
    12·1 answer
  • A tourist stands at the top of the Grand Canyon, holding a rock, overlooking the valley below. Find the final velocity, and disp
    5·2 answers
  • A race car has a mass of 710 kg. It starts from rest and travels 40 m in 3.0 s. The car is uniformly accelerated during the enti
    11·1 answer
  • The same girl in number 3 (above) pushes another friend on the same skateboard.
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!