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Gnesinka [82]
3 years ago
6

Look at the image provided, it shows forces acting on a box. What is the NET FORCE on the box?

Physics
1 answer:
faltersainse [42]3 years ago
4 0
Your answer should be C
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Suppose a rollerblade racer finished a 132 meter race in 18 seconds. What is the average speed of the rollerblade racer?
Ivanshal [37]

Answer:

7.33 rounded

Explanation:

Speed = distance divided time

S = d/t

Suppose a Rollerblade racer finished a 132 meter race in 18 seconds. What is the average speed of the Rollerblade racer?

S = 132 divided 18

Speed = 7.33 rounded

6 0
3 years ago
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Look at the picture below. The boy is swinging back and forth on the swing. At which point is the potential energy of a swing th
Ilia_Sergeevich [38]
The potential energy of a swing is greatest at the top of the swing. (Point A).
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3 years ago
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A piece of indium with a mass of 16.6 g is submerged in 46.3 cm3 of water in a graduated cylinder. The water level increases to
blagie [28]

Answer:

the density of indium is  7.2 g/cm^3

Explanation:

The computation of the density of indium is shown below:

Given that

Mass = 16.6 g

Volume = 48.6 c,^3 - 46.3cm^3 = 2.3 cm^3

Based on the above information

As we know that

Density = mass  ÷ volume

So,

= 16.6g ÷ 2.3 cm^3

= 7.2 g/cm^3

hence, the density of indium is  7.2 g/cm^3

We simply applied the above formula so that the correct value could come

And, the same is to be considered  

8 0
3 years ago
How to find initial velocity
Vaselesa [24]

Answer:

Velocity= Distance divided by time divided by degree or direction.

Explanation:

Speed=DIstance divided by time

4 0
3 years ago
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"A 75 kg swimmer dives horizontally off a 500 kg raft. If the diver's speed immediately after leaving the raft is 4 m/s, what is
svet-max [94.6K]

Answer:

0.6 m/s

Explanation:

Let the raft speed be v.

Given:

Mass of the swimmer (m) = 75 kg

Mass of the raft (M) = 500 kg

Speed of swimmer after leaving the raft (u) = 4 m/s

Now, the given situation can be considered a problem of conservation of total momentum before and after collision.

Momentum is the product of mass and velocity.

Here, the swimmer and raft are the bodies in collision.

So, before the collision, both the bodies were at rest. So, initial momentum is 0. Now, from conservation of momentum, the final momentum of the system must be 0 after the collision. Therefore,

Final Momentum = 0

mu+Mv=0\\\\Mv=-mu\\\\v=-\dfrac{mu}{M}

Plug in the given values and solve for 'v'. This gives,

v=-\frac{75\times 4}{500}\\\\v=-\frac{300}{500}=-0.6\ m/s

The final velocity of the raft is -0.6 m/s. Now, speed is the magnitude of velocity.

Therefore, the corresponding raft speed is 0.6 m/s.

7 0
4 years ago
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