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3 years ago

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Un cuerpo que pesa 80 N cae libremente, cuando se encuentra a 9 metros de altura su velocidad es 5 m/s. determina su energía cin

ética y su energía potencial gravitatoria.

1 answer:

Over [174]3 years ago

6 0

Explanation:

Taking g = 10m/s^-2

v = 5 m/s

weight = mg = 80 N

Mass = 8 kg

$kinetic \: energy \: = \frac{1}{2} m {v}^{2}$

K.E. = 1 /2 * 8 * 5* 5

Kinetic Energy = 100 J

$potential \: energy \: = mgh$

P. E. = 8 * 10 * 9

Potential Energy = 720 J

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Answer:

$\frac{F_1}{F_2}=3.55$

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Dividing the above two equations we get

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The ratio of the drag forces is $\mathbf{\frac{F_1}{F_2}}=\mathbf{3.55}$

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3 years ago

Absolute potential difference ,due of point charge of 1C at a distance of 1 m is given by

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Please help! I especially need help with the second question but help with the first one would be most appreciated!

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Answer:

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