3 years ago

How does electricity turn into light in a common lightbulb?

Physics

2 answers:

Pachacha [2.7K]3 years ago

8 0

Answer:

i think its B

Explanation:

im pretty sure.

Travka [436]3 years ago

3 0

It’s b garunteed I promise

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Which of the following elements has the lowest electronegativity?

wlad13 [49]

Answer:I believe it is D I might be wrong

Explanation:

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3 years ago

A body in simple harmonic motion has a displacement x that varies in time t according to the equation x = 5cos(π t + π/3) , wher

zhuklara [117]

Answer:

1/2 Hz

Explanation:

A simple harmonic motion has an equation in the form of

$x(t) = Acos(\omega t - \phi)$

where A is the amplitude, $\omega = 2\pi f$ is the angular frequency and $\phi$ is the initial phase.

Since our body has an equation of x = 5cos(π t + π/3) we can equate $\omega = \pi$ and solve for frequency f

$2\pi f = \pi$

f = 1/2 Hz

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3 years ago

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The relative highness or lowness of a sound is called ______. Multiple Choice pitch timbre dynamics octave

Assoli18 [71]

Pitch is the answer…….

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2 years ago

1. What is the pull that all objects exert on each other?

Andrei [34K]

Answer:

Im pretty sure 1 is gravity, 2 is force

Explanation:

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3 years ago

An electron is accelerated within a particle accelerator using a 100 MV electric potential. The 100 MeV electron moves along an

Delicious77 [7]

Answer:

The length of the tube is 3.92 m.

Explanation:

Given that,

Electric potential = 100 MV

Length = 4 m

Energy = 100 MeV

We need to calculate the value of $\gamma$

Using formula of relativistic energy

$E=m_{0}c^2(\dfrac{1}{\sqrt{1-\dfrac{v^2}{c^2}}}-1)$

Put the value into the formula

$1.6\times10^{-15}= 9.1\times`10^{-31}\times9\times10^{16}(\dfrac{1}{\sqrt{1-\dfrac{v^2}{c^2}}}-1)$

$(\dfrac{1}{\sqrt{1-\dfrac{v^2}{c^2}}}-1)=\dfrac{1.6\times10^{-15}}{9.1\times10^{-31}\times9\times10^{16}}$

Here, $\gamma-1=(\dfrac{1}{\sqrt{1-\dfrac{v^2}{c^2}}}-1)$

$\gamma-1=0.01953$

$\gamma=0.01953+1$

$\gamma=1.01953$

We need to calculate the length

Using formula of length

$L'=\dfrac{L}{\gamma}$

Put the value into the formula

$L'=\dfrac{4}{1.01953}$

$L'=3.92\ m$

Hence, The length of the tube is 3.92 m.

8 0

3 years ago