2 years ago

How does electricity turn into light in a common lightbulb?

Physics

2 answers:

Pachacha [2.7K]2 years ago

8 0

Answer:

i think its B

Explanation:

im pretty sure.

Travka [436]2 years ago

3 0

It’s b garunteed I promise

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A mass resting on a horizontal, frictionless surface is attached to one end of a spring; the other end is fixed to a wall. It ta

My name is Ann [436]

Answer:

a). $K=528.92 \frac{N}{m}$

b). $m=4.84kg$

Explanation:

a).

The work of the spring is find by the formula:

$w_s =\frac{1}{2}*k*x^2$

So knowing the work can find the constant K'

$3.2J =\frac{1}{2}*k*(0.11m)^2$

Solve for K'

$K=\frac{2*W_s}{x^2}=\frac{2*3.2J}{0.11m^2}$

$K=528.92 \frac{N}{m}$

b).

The force of the spring realice a motion so using the force and knowing the accelerations can find the mass

$F=m*a$

$m=\frac{F}{a}=\frac{K*x}{a}$

$m=\frac{528.9*0.11m}{12m/s^2}$

$m=4.84kg$

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2 years ago

Rosa uses the formula (vi cos)t to do a calculation. Which value is Rosa most likely trying to find? the vertical acceleration o

blagie [28]

The horizontal displacement of a projectile launched at an angle

4 0

2 years ago

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(a) The volume flow rate in an artery supplying the brain is 3.4 x 10-6 m3/s. If the radius of the artery is 5.6 mm, determine t

UNO [17]

Answer: a) speed = 3.45 × 10^-2 m/s

b) speed = 1.38 × 10^-1 m/s

Explanation: shown in the attachment

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3 years ago

A student drops a rock from a bridge to the water 12.7 m below. with what speed does the rock strike the water? the acceleration

kolezko [41]

The rock strike the water with the speed of 15.78 m/sec.

The speed by which rock hit the water is calculated by the formula

v= $\sqrt{2gh}$

v= $\sqrt{2*9.8*12.7}$

v=15.78 m/sec

Hence, the rock strike the water with the speed of 15.78 m/sec.

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2 years ago

A baseball has a mass of 0.145 kilograms, and a bowling ball has a mass of 6.8 kilograms. What is the gravitational force betwee

larisa [96]

We can use the equation for Newton's Law of Gravitation
Fg = (Gm₁m₂)/r²
Where gravitational constant = G = 6.674 x 10⁻¹¹ N · m²/kg²
mass m₁ = 0.145 kg
mass m₂ = 6.8 kg
distance between centers of masses = r = 0.5 m

Substitute these values into...
Fg = (Gm₁m₂)/r²
Fg = ((6.674 x 10⁻¹¹)(0.145)(6.8)) / (0.5)²
Fg = 2.63 x 10⁻¹⁰ N

Therefore, your answer should be <span>2.6 × 10–10</span>

8 0

3 years ago

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