1 answer:
You might be interested in
Answer:
(2,3)
Step-by-step explanation:
We are given that triangle PQR lies in the xy-plane, and coordinates of Q are (2,-3).
Triangle PQR is rotated 180 degrees clockwise about the origin and then reflected across the y-axis to produce triangle P'Q'R',
We have to find the coordinates of Q'.
The coordinates of Q(2,-3).
180 degree clockwise rotation about the origin then transformation rule
The coordinates (2,-3) change into (-2,3) after 180 degree clockwise rotation about origin.
Reflect across y- axis the transformation rule
Therefore, when reflect across y- axis then the coordinates (-2,3) change into (2,3).
Hence, the coordinates of Q(2,3).
Because the coefficient of x^2 is -1, we know that a will be -1. Knowing that the coefficient of x is -4, we can calculate that p=2. Thus, we have -1(x+2)^2+q is our equation. This is equal to -x^2-4x-4+q. As the constant term must be 2, we can then see that q is 6.
As such, we have -1(x+2)^2+6=0 as our factorization.
To solve this equation, we can use the quadratic formula. Plugging in values, we have:
which is equal to: (when the fraction is simplified)
As such, we have -1(x+2)^2+6=0 as our factorization.
To solve this equation, we can use the quadratic formula. Plugging in values, we have:
which is equal to: (when the fraction is simplified)