Which is an example of sliding friction?

Physics

1 answer:

stepan [7]3 years ago

5 0

Answer:

You rubbing your hands together

Your hands are sliding against each other

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If a bicyclist, with initial velocity of zero, steadily gained speed until reaching a final velocity of 26m/s, how far would she

svetlana [45]

Answer:

34.45m

Explanation:

Using the equation of motion formula v² = u²+2as to get the distance travelled

v is the final velocity = 26m/s

u is the initial velocity = 0m/s

a is the acceleration due to gravity = 9.81m/s²

S is the distance travelled

Substituting the given values into the formula;

26² = 0²+2(9.81)s

676 = 0 + 19.62s

19.62s = 676

s = 676/19.62

s = 34.45m

Hence the distance she would travel during the race is 34.45m

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3 years ago

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aleksandrvk [35]

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3 years ago

Calculate the ratio of the drag force on a jet flying at 950 km/h at an altitude of 10 km to the drag force on a prop-driven tra

Black_prince [1.1K]

Answer:

$\frac{F_1}{F_2}=3.55$

Explanation:

F = Force

C = Drag coefficient equal for both aircrafts

ρ = Density of air

A = Surface area equal for both aircrafts

v = Velocity

$v_2=\frac{2}{5}v_1$

$F_1=\frac{1}{2}\rho_1 CAv_1^2$

$F_2=\frac{1}{2}\rho_2 CAv_2^2\\\Rightarrow F_2=\frac{1}{2}\rho_2 CA\left(\frac{2}{5}v_1\right)^2$

Dividing the above two equations we get

$\frac{F_1}{F_2}=\frac{\frac{1}{2}\rho_1 CAv_1^2}{\frac{1}{2}\rho_2 CA\left(\frac{2}{5}v_1\right)^2}\\\Rightarrow \frac{F_1}{F_2}=\frac{\rho_1}{\rho_2\frac{4}{25}}\\\Rightarrow \frac{F_1}{F_2}=\frac{0.38}{0.67\frac{4}{25}}\\\Rightarrow \frac{F_1}{F_2}=3.55$