Sample Response: The water is cooler than the sand because it has a higher specific heat value. This means that it takes longer for the water to increase in temperature, making it feel cooler than the sand, which warms up more quickly.
Answer:
Work done by external force is given as

Explanation:
As per work energy Theorem we can say that work done by all force on the car is equal to change in kinetic energy of the car
so we will have

now we have


so from above equation

so from above equation work done by external force is given as

Answer:
b) 1.29 V
Explanation:
Potential Difference: This is the work done when one coulomb of charge moves from one point to another in an electric field
The expression for the potential difference is
Q = CV .................... Equation 1
Where Q = amount of charge, C = Capacitance of the capacitor, V = potential difference.
Making V the subject of the equation,
V = Q/C................. Equation 2
Given: Q = 4.5 µC = 4.5×10⁻⁶ C, C = 3.5 µF = 3.5×10⁻⁶ F
Substituting into equation 2
V = 4.5×10⁻⁶ /3.5×10⁻⁶
V = 1.2857 V
V ≈ 1.29 V.
Hence the right option is b) 1.29 V
Answer:
i believe B, my apologies if wrong, let me know if it was wrong so I can correct myself
Explanation: