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lbvjy [14]
2 years ago
6

A person experiencing heat

Physics
1 answer:
balu736 [363]2 years ago
7 0

Answer:

it will be heavy sweating

Explanation:

because if humans expierment a heavy heat they might be sweating heavly

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How do you know the earth is rotating on its axis
cupoosta [38]

Answer:

Read below!

Explanation:

You can watch the sun wheel across the sky during the day, and the stars at night. Focus a telescope on any star besides the north star--especially southern stars--and you can watch them drift across your field of view.  

An alternative explanation is that all the stars are painted on (or holes in) some canopy that rotates around the earth. This explanation does not account for the motion of the "wanderers," or planets, as the Greeks called them, or for the path of the moon among the stars.  

As we know the stars are massive bodies of significant and varying distance to the earth, the notion they all swing around us in unison seems highly implausible

4 0
3 years ago
Will give brainliest to right answer!
viva [34]
The correct answer is D.
8 0
3 years ago
A rubber band has potential energy of 5 J. If the spring constant of the rubber band is 50 N/m, what is the displacement of the
Valentin [98]
To determine the displacement, since we are given the potential energy, we use the equation for potential energy. For a spring, it is one-half the product of the spring constant and the square of the displacement. We do as follows:

PE = kx^2/2
5 Nm = 50N/m (x^2)
x = 0.32 m

Therefore, the displacement would be 0.32 m.
7 0
3 years ago
Read 2 more answers
An inductor has an inductance of 0.12 mH. Calculate the number of turns per unit length of this inductor if it has a total of 50
SSSSS [86.1K]

Answer:

oh                      

Explanation:

5 0
2 years ago
Unpolarized light with intensity I0I0I_0 is incident on an ideal polarizing filter. The emerging light strikes a second ideal po
zvonat [6]

Answer:

0.293I_0

Explanation:

When the unpolarized light passes through the first polarizer, only the component of the light parallel to the axis of the polarizer passes through.

Therefore, after the first polarizer, the intensity of light passing through it is halved, so the intensity after the first polarizer is:

I_1=\frac{I_0}{2}

Then, the light passes through the second polarizer. In this case, the intensity of the light passing through the 2nd polarizer is given by Malus' law:

I_2=I_1 cos^2 \theta

where

\theta is the angle between the axes of the two polarizer

Here we have

\theta=40^{\circ}

So the intensity after the 2nd polarizer is

I_2=I_1 (cos 40^{\circ})^2=0.587I_1

And substituting the expression for I1, we find:

I_2=0.587 (\frac{I_0}{2})=0.293I_0

5 0
2 years ago
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