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nadya68 [22]
3 years ago
5

Broccoli cost 1.50 per pound at the shop. How much money does 64 ounces of broccoli cost, before tax?

Mathematics
1 answer:
olga2289 [7]3 years ago
8 0
The brocoli would cost 6 dollars.
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How will the solution of the system y > 2x + and y < 2x + change if the inequality sign on both inequalities is reversed t
Gala2k [10]

Answer:

The System of inequality is ,

1. y > 2 x + p

2. y < 2 x + p

Suppose we assign some values to p and q and draw its graph

And, then the inequality sign on both inequalities is reversed

3. y < 2 x + p

4. y > 2 x + p

And , then draw it's graph

it has been found that, the solution set of both the inequality remains same.That is there is no point or set of points , which satisfy both the system of inequality.

The system has no solution.

5 0
3 years ago
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The area of a rectangle is 44 m²<br> The width is 3 2/3m<br> Work out the missing length?
Alika [10]

Answer:

12 meter

Step-by-step explanation:

We know that ,

Area of rectangle = length × breadth

so,44m square = l × 3 2/3 m

or, 44m2 = length × 11/3

or ,( 44m2)/3 2/3m = length

finally, length = 12 meters

3 0
3 years ago
Please answer the following questions​
laila [671]

Answer:

4a) 110 square centimetres

4b) 127 square centimetres

6) 292 square centimetres

8) 800 tiles

Step-by-step explanation:

4. We need to find the area of the large rectangle and then deduct the area of the unshaded part:

a) The large rectangle has dimensions 12 cm by 15 cm. Its area is:

A = 12 * 15 = 180 square centimetres

The unshaded part has a length of 15 - (3 + 2) cm i.e. 10 cm and a width of 7 cm. Its area is:

a = 10 * 7 = 70 square centimetres

Therefore, the area of the shaded part is:

A - a = 180  - 70 = 110 square centimetres

b) The large rectangle has dimensions 13 cm by 11 cm. Its area is:

A = 13 * 11 = 143 square centimetres

The unshaded part has dimensions 8 cm by 2 cm. Its area is:

a = 8 * 2 = 16 square centimetres

Therefore, the area of the shaded part is:

A - a = 143 - 16 = 127 square centimetres

6. The background area of the space not covered by the photograph is the area of the frame minus the area of the photograph.

The frame has dimensions 24 cm by 18 cm. Therefore, its area is:

A = 24 * 18 = 432 square centimetres

The photograph has dimensions 14 cm by 10 cm. Therefore, its area is:

a = 14 * 10 = 140 square centimetres

Therefore, the background area of the space not covered by the photograph is:

A - a = 432 - 140 = 292 square centimetres

8) The floor has dimensions 8 m by 4 m. The area of the floor is:

A = 8 * 4 = 32 square centimetres

Each square tile has dimensions 20 cm by 20 cm. In metres, that is 0.2 m by 0.2 m. The area of each tile is:

a = 0.2 * 0.2 = 0.04 square metres

The number of tiles that are needed is the area of the floor divided by the area of each tile:

A / a = 32 / 0.04 = 800 tiles

4 0
3 years ago
Helppppppp!!!! me ill put you brainliest!
Damm [24]

Answer:

21 3/4 - 13 1/8 = 8 5/8 ft longer

Step-by-step explanation:

We subtract the blue rope from the green rope

21 3/4 - 13 1/8

We need to get a common denominator of 8

21 3/4*2/2 - 13 1/8

21 6/8 - 13 1/8

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4 0
3 years ago
Question is in the picture.
STALIN [3.7K]

Answer:

3

Step-by-step explanation:

5 0
3 years ago
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