1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Goryan [66]
3 years ago
7

A car is traveling with a velocity of 5.5 m/s and has a mass of 1200 kg. What is the kinetic energy?!

Physics
1 answer:
vesna_86 [32]3 years ago
3 0

Answer:

<h2>18150 J</h2>

Explanation:

The kinetic energy of the car can be found by using the formula

k =  \frac{1}{2} m {v}^{2}  \\

m is the Mass

v is the velocity

From the question we have

k =  \frac{1}{2}  \times 1200 \times  {5.5}^{2}  \\  = 600 \times 30.25

We have the final answer as

<h3>18150 J</h3>

Hope this helps you

You might be interested in
Water at room temperature is discharged from a pipe at a rate of 1000 gallons per minute (gpm). Express this flow rate in cubic
marshall27 [118]

Answer

given,

discharge rate from pipe = 1000 gallons/minutes

now,

flow rate in  cubic meters per second

1 gallon = 0.00378541 m³

1 min = 60 s

Q = 1000\times \dfrac{0.00378541\ m^3}{1\ gallon}\times \dfrac{1\ min}{60\ s}

Q = 0.063 m³/s

flow rate in  liters per minute

1 gallon = 3.78541 L

 Q = 1000\times \dfrac{3.78541\ m^3}{1\ gallon}

 Q = 3785.41 m³/min

flow rate in cubic feet per second

 1 gallon = 0.133681 ft³

 1 min = 60 s

Q = 1000\times \dfrac{0.133681\ ft^3}{1\ gallon}\times \dfrac{1\ min}{60\ s}

Q = 2.23 ft³/s

4 0
3 years ago
Find the magnitude of the force at point x = 15cm if k=10500 N/m when the work done by this force is WD= 1/2k x2
Ann [662]

Answer:

sqdqk3

Explanation:

qdjqưbdkq ưqdhud j

6 0
3 years ago
a ball kicked with a velocity of 8m/s at an angle of 30 degree to horizontal. calculate the time of flight of the ball. (g=10ms^
posledela

Answer:

Approximately 0.8\; \rm s (assuming that air resistance is negligible.)

Explanation:

Let v_0 denote the initial velocity of this ball. Let \theta denote the angle of elevation of that velocity.

The initial velocity of this ball could be decomposed into two parts:

  • Initial vertical velocity: v_0(\text{vertical}) = v_0 \cdot \sin(\theta).
  • Initial horizontal velocity: v_0(\text{vertical}) = v_0 \cdot \cos(\theta).

If air resistance on this ball is negligible, v_0(\text{vertical}) alone would be sufficient for finding the time of flight of this ball.

Calculate v_0(\text{vertical}) given that v_0 = 8 \; \rm m \cdot s^{-1} and \theta = 30^\circ:

\begin{aligned}& v_0(\text{vertical}) \\ &= v_0 \cdot \sin(\theta) \\ &= \left(8 \; \rm m \cdot s^{-1} \right) \cdot \sin\left(30^{\circ}\right) \\ &= 4\;\rm m \cdot s^{-1} \end{aligned}.

Assume that air resistance on this ball is zero. Right before the ball hits the ground, the vertical velocity of this ball would be exactly the opposite of the value when the ball was launched.

Since v_0(\text{vertical}) = 4\; \rm m \cdot s^{-1}, the vertical velocity of this ball right before landing would be v_1(\text{vertical}) = -4\; \rm m \cdot s^{-1}.

Calculate the change to the vertical velocity of this ball:

\begin{aligned}& \Delta v(\text{vertical}) \\ & = v_1(\text{vertical}) - v_0(\text{vertical}) \\ &= -8\; \rm m \cdot s^{-1}\end{aligned}.

In other words, the vertical velocity of this ball should have change by 8\; \rm m \cdot s^{-1} during the entire flight (from the launch to the landing.)

The question states that the gravitational field strength on this ball is g = 10\; \rm m \cdot s^{-2}. In other words, the (vertical) downward gravitational pull on this ball could change the vertical velocity of the ball by 10\; \rm m\cdot s^{-1} each second. What fraction of a second would it take to change the vertical velocity of this ball by 8\; \rm m \cdot s^{-1}?

\begin{aligned}t &= \frac{\Delta v(\text{initial})}{g} \\ &= \frac{8\; \rm m \cdot s^{-1}}{10\; \rm m \cdot s^{-2}} = 0.8\; \rm s\end{aligned}.

In other words, it would take 0.8\; \rm s to change the velocity of this ball from the initial velocity at launch to the final velocity at landing. Therefore, the time of the flight of this ball would be 0.8\; \rm s\!.

5 0
3 years ago
Why reaction force must exist
Fittoniya [83]
Newton's 3rd law:
Every action has an equal and opposite reaction.
When you apply force on an object, there is an equal force applied on you from that object.
7 0
3 years ago
A rock is dropped into a canyon that is 0.3 km deep. Determine the time it takes the rock to hit the bottom of the canyon?
Zigmanuir [339]

Answer:

rock of mass m is dropped to the ground from a height h. A second rock, with mass 2m, is dropped from the same height. When the second rock strikes the ground, what is its kinetic energy? (a) Twice that of the first rock, (b) four times that of the first rock, (c) same as that of the first rock, (d) half as much as that of the first rock, (e) impossible to determine.

8 0
3 years ago
Other questions:
  • For every action
    5·1 answer
  • Moving a magnet inside a coil of wire will induce a voltage in the coil. How can the voltage in the coil be increased?
    13·2 answers
  • Complete these sentences. If a bouncing ball has a total energy of 20 J and a kinetic energy of 5 J, the ball’s potential energy
    9·2 answers
  • Which set of electromagnetic waves is in the correct order from greatest to least energy?
    11·1 answer
  • Which is described as the flow of charge particles?
    14·1 answer
  • A dog walks a distance of 55.5 meters in 120 seconds. What was its speed?
    11·1 answer
  • A sodium has an atomic number of 11 and the atomic mass of 23. Determine the its proton, electrons, and neutrons
    5·1 answer
  • Newspapers often talk about an energy crisis-about running out of certain energy sources in the not-so-distant future. About whi
    13·1 answer
  • PLEASE HELP WITH EXPLANATION! I WILL GIVE YOU BRAINLIEST!
    11·1 answer
  • Which is not a detritivore<br>a. maggots<br>b.worms<br>c.dung flies<br>d.squirrels​
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!