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3 years ago

What’s the derivative of sin^2(cos(x^2))

Mathematics

1 answer:

Varvara68 [4.7K]3 years ago

7 0

Answer: f'(x) = - cos^2(sin(x^2))

Step-by-step explanation:

Derivative of:

f(x) = Sin^2(cos(x^2))

f'(x) = cos^2(-sin(x^2)

f'(x) = - cos^2(sin(x^2))

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I need help..............

vovangra [49]

Answer:

$a_n=-3+7(n-1)$

Step-by-step explanation:

The recursive rule tells you the initial term of the sequence is a1 = -3, and the common difference is d=7. (7 is the value added to one term to get the next term.)

Putting these values into the formula for the explicit rule gives ...

an = a1 +d(n -1)

an = -3 + 7(n -1)

7 0

3 years ago

What are the possible lengths of side Ab in a triangle which the given side lengths of 3 and 5 cm?

natali 33 [55]

Answer:

Plug this in a calculator and the answer will pop up.

Step-by-step explanation:

$\sqrt{5^{2} +3^{2}$

5 0

3 years ago

Which expression is equivalent to (3 x^ 2 - 7)

Kay [80]

Answer:

What are the posible answers for the question?

Step-by-step explanation:

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2 years ago

G. If two triangles have three corresponding angles and three corresponding sides that are

Alex777 [14]

Answer:

Yes.

Step-by-step explanation:

Yes they are because that is the definition of congruency.

4 0

3 years ago

Evaluate the following limit:

Makovka662 [10]

If we evaluate the function at infinity, we can immediately see that:

$\large\displaystyle\text{$\begin{gathered}\sf \bf{\displaystyle L = \lim_{x \to \infty}{\frac{(x^2 + 1)^2 - 3x^2 + 3}{x^3 - 5}} = \frac{\infty}{\infty}} \end{gathered}$}$

Therefore, we must perform an algebraic manipulation in order to get rid of the indeterminacy.

We can solve this limit in two ways.

By comparison of infinities:

We first expand the binomial squared, so we get

$\large\displaystyle\text{$\begin{gathered}\sf \displaystyle L = \lim_{x \to \infty}{\frac{x^4 - x^2 + 4}{x^3 - 5}} = \infty \end{gathered}$}$

Note that in the numerator we get x⁴ while in the denominator we get x³ as the highest degree terms. Therefore, the degree of the numerator is greater and the limit will be \infty. Recall that when the degree of the numerator is greater, then the limit is \infty if the terms of greater degree have the same sign.

Dividing numerator and denominator by the term of highest degree:

$\large\displaystyle\text{$\begin{gathered}\sf L = \lim_{x \to \infty}\frac{x^{4}-x^{2} +4 }{x^{3}-5 } \end{gathered}$}\\$

$\ \ = \lim_{x \to \infty\frac{\frac{x^{4} }{x^{4} }-\frac{x^{2} }{x^{4}}+\frac{4}{x^{4} } }{\frac{x^{3} }{x^{4}}-\frac{5}{x^{4}} } }$

$\large\displaystyle\text{$\begin{gathered}\sf \bf{=\lim_{x \to \infty}\frac{1-\frac{1}{x^{2} } +\frac{4}{x^{4} } }{\frac{1}{x}-\frac{5}{x^{4} } } \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =\frac{1}{0}=\infty } \end{gathered}$}$

Note that, in general, 1/0 is an indeterminate form. However, we are computing a limit when x →∞, and both the numerator and denominator are positive as x grows, so we can conclude that the limit will be ∞.

5 0

2 years ago