Question

Using the following equation how many grams of pure oxygen do you need to comsume 635.2g of glucose: C6H12O6 + 6O2 → 6CO2 + 6H2O + energy

Answer 1

Answer:

677.76 g of oxygen needed.

Explanation:

Given data:

Mass of glucose = 635.2 g

Mass of oxygen needed = ?

Solution:

Chemical equation:

C₆H₁₂O₆  + 6O₂  →  6CO₂ + 6H₂O + energy

Number of moles of glucose:

Number of moles = mass/ molar mass

Number of moles = 635.2 g / 180.156 g/mol

Number of moles = 3.53 mol

Now we will compare the moles of glucose with oxygen.

                         C₆H₁₂O₆           :              O₂

                               1                  :               6

                             3.53              :           6×3.53 = 21.18 mol

Mass of oxygen:

Mass = number of moles × molar mass

Mass =  21.18 g × 32 g/mol

Mass = 677.76 g