1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Iteru [2.4K]
3 years ago
12

How many milliliters are in a 30 gallon drum?

Chemistry
2 answers:
sertanlavr [38]3 years ago
8 0

Answer:

113562  milliliters are in a 30 gallon drum

Explanation:

because you have to convert gallons into milliliters

could you put my answer as the brainist!!!!!!!

Aneli [31]3 years ago
7 0
113562.354 milliliters
You might be interested in
How many grams of Co3+ are present in 2.34 grams of cobalt(III) nitrite?
Assoli18 [71]

Answer:

m_{Co^{3+}}=0.563gCo^{3+}

Explanation:

Hello there!

In this case, since these mole-mass relationships are understood in terms of the moles of the atoms forming the considered compound, we first realize that the chemical formula of the cobalt (III) nitrate is Co(NO₃)₃ whereas there is a 1:1 mole ratio of the cobalt (III) ion (molar mass = 58.93 g/mol) to the entire compound. In such a way, we first compute the moles of the salt (molar mass = 58.93 g/mol) and then apply the aforementioned mole ratio to obtain the grams of the required cation:

m_{Co^{3+}}=2.34gCo(NO_3)_3*\frac{1molCo(NO_3)_3}{244.95 gCo(NO_3)_3} *\frac{1molCo^{3+}}{1molCo(NO_3)_3} *\frac{58.93gCo^{3+}}{1molCo^{3+}} \\\\m_{Co^{3+}}=0.563gCo^{3+}

Best regards!

4 0
2 years ago
How many atoms are in Sodium, Carbon, Hydrogen, Oxygen, Fluorine, Boron, Lithium, Helium, Phosphorus and Sulfur?
vlada-n [284]
Sodium. 11
Carbon. 12
Hydrogen 1
Oxygen 2
Fluuorine. 14
Boron. 5
Lithium. 6
Helium 3
Phosphorus 15
Sulfur 6
6 0
3 years ago
In a neutral solution, the concentration of H+ is
Elan Coil [88]

Answer:

1 x 10^-7 or 7

Explanation:

pH=-log(H+)

pH+pOH=14

5 0
2 years ago
How many molecules are in 41.8 g of sulfuric acid
Anton [14]

Answer

× 10²³ molecules are in 41.8 g of sulfuric acid

Explanation

The first step is to convert 41.8 g of sulfuric acid to moles by dividing the mass of sulfuric acid by its molar mass.

Molar mass of sulfuric acid, H₂SO₄ = 98.079 g/mol

Mole=\frac{Mass}{Molar\text{ }mass}=\frac{41.8\text{ }g}{98.079\text{ }g\text{/}mol}=0.426187053\text{ }mol

Finally, convert the moles of sulfuric acid to molecules using Avogadro's number.

Conversion factor: 1 mole of any substance = 6.022 × 10²³ molecules.

Therefore, 0.426187053 moles of sulfuric acid is equal

\frac{0.426187053\text{ }mol}{1\text{ }mol}\times6.022×10²³\text{ }molecules=2.57\times10^{23}\text{ }molecules

Thus, 2.57 × 10²³ molecules are in 41.8 g of sulfuric acid.

3 0
9 months ago
Uso industrial hidruro mercurico
bonufazy [111]

he arsenic acid or arsenate hydrogen as it is also known to this compound (H 3 AsO 4 ) is the acid form of <span>ion </span>arsenate , AsO<span>4 </span>3- , one anion trivalent in which arsenic has an oxidation state of + 5. Chemically, arsenates behave in a similar way tophosphates .

There is another compound derived from this one that is the arsenious acid or arsenite of hydrogen

5 0
2 years ago
Other questions:
  • PLEASE ANSWERRRRRRRRRRRRRRRRR
    5·1 answer
  • Study the diagram about the varying pressures of Earth’s Layers.
    11·2 answers
  • Which reaction will occur?
    8·2 answers
  • Plzzzz HELPPPP!!!!!!!
    8·2 answers
  • Why aluminium foils are use to wrap food items
    12·2 answers
  • A 3.76 g sample of a compound consisting of carbon, hydrogen, oxygen, nitrogen, and sulfur was combusted in excess oxygen. This
    15·1 answer
  • How can an experiment support or fail support a hypothesis
    12·1 answer
  • Provide background information about different types of chemical reactions.
    11·1 answer
  • Using the average atomic masses given inside the front cover of this book, calculate the number of atoms present in each of the
    5·1 answer
  • Recessive genes are _____.
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!