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2 years ago

I need help plss asap

Chemistry

1 answer:

Basile [38]2 years ago

8 0

Answer:

Volume = mass/density

Rearrange the equation for Mass:

Mass = Volume x Density

That is one way you can do it

Conceptually, just look at the units, the wood block's density is 0.6<u>g/cm^3</u> while the volume is 2.2 <u>cm^3</u>

So if density is every gram per centimeter cubed, and the volume is at centimeter cubed, the logical thing to do would be to multiply the density by the volume to get the total mass.

0.6g/cm^3 x 2.2cm^3 = 1.32g

<u>Therefore the mass of the block of wood is 1.32g </u>

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Will someone please help me with numbers 22-26? I would really appreciate it. Thank you.

Naddika [18.5K]

Do You Mean 22 - 26 = 4

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4 years ago

D = 24 g/ml<br> v = 1200 ml<br> m = ?

8_murik_8 [283]

Answer:

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

mass = Density × volume

From the question we have

mass = 24 × 1200

We have the final answer as

Hope this helps you

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3 years ago

What are the casues of global warming?

zhannawk [14.2K]

Answer: Carbon emissions

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3 years ago

Q4. The student started with 16.0 grams of NaCl, show the calculation for the percent error that

Vedmedyk [2.9K]

Answer:

72.6% Error

Explanation:

% error = $\frac{Real-Measured}{Real} * 100$

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3 years ago

The energy content of food is typically determined using a bomb calorimeter. Consider the combustion of a 0.22-g sample of butte

iren2701 [21]

Answer: The energy of combustion of butter is 31.5 kJ/g

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

$Q=C\times \Delta T$

Q = Heat absorbed by calorimeter =?

C = heat capacity of calorimeter = $2.67kJ/^0C$

Initial temperature of the calorimeter = $T_i$ = $23.5^0C$

Final temperature of the calorimeter = $T_f$ = $26.1^0C$

Change in temperature , $\Delta T=T_f-T_i=(26.1-23.5)^0C=2.6^0C$

Putting in the values, we get:

$Q=2.67kJ/^0C\times 2.6^0C=6.94kJ$

As heat absorbed by calorimeter is equal to heat released by combustion of butter

$Q=q$

Heat released by 0.22 g of butter = 6.94 kJ

Heat released by 1g of butter = $\frac{6.94}{0.22}\times 1=31.5kJ$

The energy of combustion of butter is 31.5 kJ/g

8 0

3 years ago