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lana66690 [7]
3 years ago
7

How many atoms of h are in 1 mol of (nh42so4?

Chemistry
1 answer:
dem82 [27]3 years ago
8 0
1 mole of NH42SO4 contains 42 moles of H. We take the 42 moles of H and multiply that times Avogadro's number (6.02x10^23) and get 2.5284x10^25 atoms of hydrogen
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Which statement about protons is false?
Alekssandra [29.7K]

<u>Answer:</u> The correct answer is Option 4.

<u>Explanation:</u>

There are three sub-atomic particles present in an atom. They are: electrons, protons and neutrons.

Protons constitute in each and every atom.

The charge on proton is of equal magnitude as that of electron but having opposite sign. Proton carry a positive charge and electron carry a negative charge.

Protons and neutrons, both determine the mass of an atom.

Mass of 1 proton = 1.007276 u

Mass of 1 neutron = 1.008664 u

Mass of 1 electron = 0.00054858 u

Mass of proton is almost same as that of neutron but is more than the mass of electron.

Hence, the correct answer is Option 4.

6 0
3 years ago
A 25.0 mL sample of sulfuric acid is completely neutralized by adding 32.8 mL of 0.116 mol/L ammonia solution. Ammonium sulfate
Paul [167]

Answer:

0.08 mol L-1

Explanation:

Sulfuric acid Formula: H2SO4

Ammonia Formula: NH3

Ammonium sulfate Formula: (NH₄)₂SO₄

H2SO4 + 2NH3 = 2NH4+ + SO4 2-

H2SO4 + 2NH3 = (NH₄)₂SO₄

H2SO4 = (1/2)x (32.8 x 10^-3 L x 0.116 mol L-1)/25 x 10^-3 L

= 0.08 mol L-1

7 0
3 years ago
Find the mass of 175.4mL of benzene if the density is 0.8786g/ml
bulgar [2K]
Hey there!:

Volume = 175.4 mL

density = 0.8786 g/mL  

mass = ?

Therefore:

D = m / V

0.8786 = m / 175.4

m = 0.8786 * 175.4

m = 154.10644 g

hope this helps!


5 0
3 years ago
Animal and plant cells all have the following organelles
pav-90 [236]

Answer: C

Explanation: They both contain membrane-bound organelles such as the nucleus, mitochondria, endoplasmic reticulum, Golgi apparatus, lysosomes, and peroxisomes.

5 0
3 years ago
How many particles are in 47.7 g of Magnesium? (Round the average
Lynna [10]

Answer:

1.18 × 10²⁴ particles Mg

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

<u>Step 1: Define</u>

47.7 g Mg

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of Mg - 24.31 g/mol

<u>Step 3: Convert</u>

<u />47.7 \ g \ Mg(\frac{1 \ mol \ Mg}{24.31 \ g \ Mg} )(\frac{6.022 \cdot 10^{23} \ particles \ Mg}{1 \ mol \ Mg} ) = 1.18161 × 10²⁴ particles Mg

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

1.18161 × 10²⁴ particles Mg ≈ 1.18 × 10²⁴ particles Mg

3 0
3 years ago
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