Question

Find the inverse, g−1(x), of the following function: g(x) = 4x - 11

Answer 1

Answer:

$g^{-1}$ (x) = $\frac{x+11}{4}$

Step-by-step explanation:

let y = g(x) and rearrange making x the subject, that is

y = 4x - 11 ( add 11 to both sides )

y + 11 = 4x ( divide both sides by 4 )

$\frac{y+11}{4}$ = x

Change y back into terms of x , with x = $g^{-1}$ (x) , thus

$g^{-1}$(x) = $\frac{x+11}{4}$