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mestny [16]
3 years ago
8

Ann increased the quantities of all the ingredients in a recipe by 60% She used 80 grams (g) of cheese How much cheese did the r

ecipe require?
Mathematics
1 answer:
Delvig [45]3 years ago
3 0

Answer:g = 50 g

Step-by-step explanation:

She used 60% more than required ⇒ she used (1+0.60)=1.60 times what was required.

x = grams required by the recipe

80 g = 1.60x

x = (80/1.60) g = 50 g

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3/4 of the weight of a bunch of grapes is equivalent to 3/5 of the weight of a papaya. If the grapes way (X +28) pounds what is
Margaret [11]
Let p = weight of papaya and g = weight of grapes.

Then (3/4)g = (3/5)p.  Since the weight of grapes is x + 28, 

(3/4)(x + 28) = (3/5)p.  We must solve for x.  To do this, mult. both sides by (5/3):

(5/3)(3/4)(x+28) = (5/3)(3/5)p

Then p = (15/9)(x+28), or (after reduction), p = (5/3)(x+28).


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3 years ago
For each part, give a relation that satisfies the condition. a. Reflexive and symmetric but not transitive b. Reflexive and tran
Vesnalui [34]

Answer:

For the set X = {a, b, c}, the following three relations satisfy the required conditions in (a), (b) and (c) respectively.

(a) R = {(a,a), (b,b), (c, c), (a, b), (b, a), (b, c), (c, b)} is reflexive and symmetric but not transitive .

(b) R = {(a, a), (b, b), (c, c), (a, b)} is reflexive and transitive but not symmetric .

(c) R = {(a,a), (a, b), (b, a)} is symmetric and transitive but not reflexive .

Step-by-step explanation:

Before, we go on to check these relations for the desired properties, let us define what it means for a relation to be reflexive, symmetric or transitive.

Given a relation R on a set X,

R is said to be reflexive if for every a \in X, (a,a) \in R.

R is said to be symmetric if for every (a, b) \in R, (b, a) \in R.

R is said to be transitive if (a, b) \in R and (b, c) \in R, then (a, c) \in R.

(a) Let R = {(a,a), (b,b), (c, c), (a, b), (b, a), (b, c), (c, b)}.

Reflexive: (a, a), (b, b), (c, c) \in R

Therefore, R is reflexive.

Symmetric: (a, b) \in R \implies (b, a) \in R

Therefore R is symmetric.

Transitive: (a, b) \in R \ and \ (b, c) \in R but but (a,c) is not in  R.

Therefore, R is not transitive.

Therefore, R is reflexive and symmetric but not transitive .

(b) R = {(a, a), (b, b), (c, c), (a, b)}

Reflexive: (a, a), (b, b) \ and \ (c, c) \in R

Therefore, R is reflexive.

Symmetric: (a, b) \in R \ but \ (b, a) \not \in R

Therefore R is not symmetric.

Transitive: (a, a), (a, b) \in R and (a, b) \in R.

Therefore, R is transitive.

Therefore, R is reflexive and transitive but not symmetric .

(c) R = {(a,a), (a, b), (b, a)}

Reflexive: (a, a) \in R but (b, b) and (c, c) are not in R

R must contain all ordered pairs of the form (x, x) for all x in R to be considered reflexive.

Therefore, R is not reflexive.

Symmetric: (a, b) \in R and (b, a) \in R

Therefore R is symmetric.

Transitive: (a, a), (a, b) \in R and (a, b) \in R.

Therefore, R is transitive.

Therefore, R is symmetric and transitive but not reflexive .

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The answer is no.

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