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Zolol [24]
3 years ago
6

What is the next sequence for 18,250, 18,500, 19,000, 20,000?

Mathematics
2 answers:
KiRa [710]3 years ago
6 0

The change in number doubles each time 22,000

olchik [2.2K]3 years ago
3 0
21,500 this is the answer
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Which expression is equivalent to (8^2)^-4
xz_007 [3.2K]

Answer:

C: \frac{1}{8*8*8*8*8*8*8*8}

Step-by-step explanation:

a^{-n} = \frac{1}{a^n}

Since a = 8^2 :

(8^2)^{-n} = \frac{1}{(8^2)^n} =\frac{1}{8^{2n}}

Since n = 4 :

(8^2)^{-4} =\frac{1}{8^{2*4}}=\frac{1}{8^{8}}=\frac{1}{8*8*8*8*8*8*8*8}

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ELEN [110]
I think you mean six-hundred and seventy six.

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5 0
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masya89 [10]

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