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3 years ago

6

A 12-sided die is rolled. The set of equally likely outcomes is {1,2,3,4,5,6,7,8,9,10,11,12}. Find the probability of rolling

a number greater than 7

2 answers:

solniwko [45]3 years ago

6 0

Need help with this , u think u can help?

MAVERICK [17]3 years ago

6 0

Answer: Probability is 4/12, or 1/3

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An analyst must decide between two different forecasting techniques for weekly sales of roller blades: a linear trend equation a

Amiraneli [1.4K]

Answer:

Following are the responses to the given question:

Step-by-step explanation:

Mean Absolute Deviation MAD

$MAD = \sum_{i=1}^{n} \frac{\left | actual_{i}-forecast_{i} \right |}{n}$

Mean squared error

$MSE=\Sigma^{n}_{i=1} \frac{(Actual_i - Forecast_i)^2}{(n - 1)}$

linear trend equation is $Ft = 124 + 2t$

$MAD = \frac{23}{10} = 2.3\\\\MSE = \frac{91}{9}= 10.11\\\\$

Naive method

$MAD = \frac{36}{9} = 4\\\\MSE = \frac{202}{8}=25.25\\\\MAD (Naive) = 4\\\\MAD (Linear) =2.3\\\\MSE (Naive)=25.25\\\\MSE (Linear)=10.11\\\\$

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A 10 sided die is numbered 1-10 if you roll it 60 times what is the best prediction for how many times you would eithrr a 1 or 2

Kamila [148]

Answer: 12

Step-by-step explanation:

So if its 1-10, and you can either roll a 1 or 2, it would be 2/10, then simplified to 1/5, and in order to get the answer you need to multiply it by 60

1/5 x 60/1 = 12

(sorry if I got it wrong, feel free to correct me if I did)

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