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levacccp [35]
3 years ago
15

A grasshopper leaps into the air at a 62° angle above the horizontal, and follows a parabolic arc in free fall after it leaves t

he ground. Mark all of the following that are true at the top of that parabolic arc?
a. The grasshopper is in equilibrium at the top of the arc.
b. The grasshopper's total velocity vector is zero.
c. The grasshopper's acceleration vector is zero.
d. None of the above.
Physics
1 answer:
harina [27]3 years ago
5 0

Answer:

d. None of the above.

Explanation:

In a parabolic motion, you have that in the complete trajectory the component velocity is constant and the vertical component changes in time. Then, the total velocity vector is not zero.

In the complete trajectory the gravitational acceleration is always present. Then, the grasshopper's acceleration vector is not zero.

At the top of the arc the grasshopper is not at equilibrium because the gravitational force is constantly acting on the grasshopper.

Then, the correct answer is:

d. None of the above.

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<u>Answer:</u>

According to newton's first law of motion, friction is required to make an object slow down.

<u>Explanation:</u>

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For example, an object which is sliding across a table or floor slows down due to the net force of friction that is acting on that object.

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Answer:

t = 0.67 [s]

Explanation:

To solve this problem we must use the following kinematics equation.

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Now replacing in the equation we have:

20 = 10 + (15*t)

t = (20-10)/15

t = 0.67 [s]

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A car is stopped at a red light. When the light changes, the car begins to accelerate at a rate of 10 m/s^2 and it continues to
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The wavelength of violet light is about 425 nm (1 nanometer = 1 × 10−9 m). what are the frequency and period of the light waves?
dexar [7]

1) Frequency: 7.06\cdot 10^{14} Hz

The frequency of electromagnetic radiation is given by:

f=\frac{c}{\lambda}

where

c = 3 \cdot 10^8 m/s is the speed of light

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In this case, the wavelength of the radiation is

\lambda=425 nm=425\cdot 10^{-9} m

Therefore the frequency is

f=\frac{3\cdot 10^8 m/s}{425 \cdot 10^{-9} m}=7.06\cdot 10^{14} Hz


2) Period: 1.42\cdot 10^{-15} s

The period is equal to the reciprocal of the frequency of the wave:

T=\frac{1}{f}

Using the frequency we found previously, f=7.06\cdot 10^{14} Hz, we find:

T=\frac{1}{7.06\cdot 10^{14} Hz}=1.42\cdot 10^{-15} s


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