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nata0808 [166]
3 years ago
15

Explain why the moon appears to go through a cycle of phases.

Physics
1 answer:
polet [3.4K]3 years ago
4 0

It is because the moon orbits around the sun so different parts of the moon is visible.

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For an object on a flat surface, the force of gravity is 10 newtons downward and the normal force is 10 newtons upward. The appl
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3 Newtons toward the right because Newton’s second law:
F = ma
15N - 12N = ma
3N = ma
(With the right being the positive direction and the left the negative direction)
3 0
2 years ago
Question 15 (3.33 points) Solve: What work is done when 3.0 C is moved through an electric potential difference of 1.5 V?
horsena [70]

Answer:

=_____________________________________

Explanation:

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3 years ago
When discussing Newton's laws of motion,which terms do people most likely yse when talking about Newton's third law of motion?​
mestny [16]

When discussing Newton's laws of motion, particularly Newton's third law of motion, the terms that almost everyone will use are "action"​ and "reaction".

You must not take this to mean that they understand what they're talking about.

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3 years ago
What is the momentum of a 0.000015 kg mosquito flying straight at you with a velocity of 5.20 m/s?
Setler [38]

Answer:

Momentum, p=7.8\times 10^{-5}\ N-m

Explanation:

Given that,

Mass of a mosquito, m = 0.000015 kg

Velocity of the mosquito, v = 5.2 m/s

We need to find the momentum of the mosquito. The momentum of an object is given by :

p = mv

Put all the values in the above formula.

p=0.000015\ kg\times 5.2\ m/s\\\\p=0.000078\ N-m\\\\\text{or}\\\\p=7.8\times 10^{-5}\ N-m

So, the momentum of the mosquito is 7.8\times 10^{-5}\ N-m.

3 0
3 years ago
A tank of volume 0.25 ft is designed to contain 50 standard cubic feet of air. The temperature is 80° F.Calculate the pressure i
slavikrds [6]

Answer:

The inside Pressure of the tank is 4499.12 lb/ft^{2}

Solution:

As per the question:

Volume of tank, V = 0.25 ft^{3}

The capacity of tank, V' = 50ft^{3}

Temperature, T' = 80^{\circ}F = 299.8 K

Temperature, T = 59^{\circ}F = 288.2 K

Now, from the eqn:

PV = nRT                      (1)

Volume of the gas in the container is constant.

V = V'

Similarly,

P'V' = n'RT'                       (2)

Also,

The amount of gas is double of the first case in the cylinder then:

n' = 2n

\]frac{n'}{n} = 2

where

n and n' are the no. of moles

Now, from eqn (1) and (2):

\frac{PV}{P'V'} = \frac{nRT}{n'RT'}

P' = 2P\frac{T'}{T} = 2\times 2116\times \frac{299.8}{288.2} = 4499.12 lb/ft^{2}

7 0
4 years ago
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