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natali 33 [55]
2 years ago
15

) The rate of submergence is the total change in the elevation of the pier (two m) divided by the total amount of time involved

(300 years) and is therefore____ cm/yr. (Remember, 1 m 5 100 cm.)
Physics
1 answer:
nevsk [136]2 years ago
4 0

Answer:

0.67cm/year

Explanation:

Since the rate of submergence is the total change in the elevation of the pier (two m) divided by the total amount of time involved (300)

We have total change in the elevation of the pier => 2m => 200cm

The total amount of time involved (300 years)

Hence, we have 200cm ÷ 300 years. = 0.67cm /yr

Therefore, in this case, the correct answer to the question is 0.67cm/year.

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197m because 132+3.0=197x
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3 years ago
Which of the following is an example of an electromagnetic wave? (2 points)
Maru [420]
A) red light
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b) ocean waves
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hope this helps!
4 0
3 years ago
Read 2 more answers
Please help me please
shusha [124]

Answer:

A

Explanation:

its A because your comparing so comparative

8 0
3 years ago
Read 2 more answers
I NEED HELP
Oduvanchick [21]

Answer:

the answer is different

Explanation:

i took the test

3 0
3 years ago
n an experiment of a simple pendulum, measurements show that the pendulum has length m, mass kg, and period s. Take m/s2 . i. Us
barxatty [35]

Answer:

The answer is "(1.265 \pm 0.010) \ s \ and \ 0.709 \%"

Explanation:

In point i:

T_{theo}= 2\pi \sqrt{\frac{l}{g}}

        =2\pi\sqrt{\frac{0.397}{9.8}}\\\\= 1.265 \ s

If  error in the theoretical time period :

\frac{\Delta T_{theo}}{T_theo} = \frac{1}{2}  \frac{\Delta l }{l}\\\\\Delta T_{theo} = 1.265 \times \frac{1}{2} \times \frac{0.006}{0.397}

           = 0.010 \ s

 T_{theo} = (1.265 \pm 0.010) \ s

In point ii:

\% \ difference = \frac{|T_{exp} -T_{theo}|}{\frac{T_{exp}+T_{theo}}{2}} \times 100

<h3>                     = \frac{1.274 -1.265}{\frac{1.274+1.265}{2}} \times 100\\\\=0.709 \%</h3>
5 0
2 years ago
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