Question

The golden gate bridge in san francisco, california is 227.4 meters above mean sea level (msl). what is the maximum distance away that an observer approaching the bridge will see the top of the highest tower? assume the eye height for a person on the boat deck is 4.3 meters above msl.

Answer 1

A normal human being can rotate his neck at maximum angle of 70 degree at one stretch

So here the maximum angle is 70 degree upto which he can see the height

now we will have

$tan\theta = \frac{H}{d}$

$tan70 = \frac{227.4 - 4.3}{d}$

now we have

$d = 81.2 m$

so he is able to see the top at minimum distance of 81.2 m from that gate