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Annette [7]
3 years ago
5

Match the concepts in Column 1 to the definitions and explanations in Column 2.

Physics
1 answer:
Akimi4 [234]3 years ago
3 0

Answer:

SRY I CAN'T ANS :( and hiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii

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The photograph shows matter going through a physical change. Which characteristic of the matter changes?
Lapatulllka [165]

Answer:

Possibly shape.

Explanation:

Because it is ripped in half. As you guys and the questioner can see that there is a wiggly strip down the middle. That also cause of a shape change.

I really hope my answer is right ^_^  

7 0
3 years ago
Read 2 more answers
The motion of a transparent medium influences the speed of light. This effect was first observed by Fizeau in 1851. Consider a l
Ket [755]

It is proved that when v<<c , then speed of the light measured in the laboratory frame is , u = c/n + v -v/n^2 .

Given ,

The motion of a transparent medium influences the speed of light .

The water moves with speed v in a horizontal pipe .

Assume that the light travels in the same direction as the water moves .

The speed of the light with respect to the water is c/n

Where n = 1.33 is the refractive index of water .

Let us assume ,

u' be the speed of light in water , in the frame moving with the water .

u' is related to the refractive index of water ,n as :

u'=c/n

where , c is the speed of light .

let , u be the speed of light in water in the lab frame .

Now , u and u' are related as : u = (u'+ v )/(1+ u'v/c^2)

Here v is the speed of water in the horizontal pipe .

we know the value of u' , so by substituting the value , we will get ,

u= (c/n+ v)/(1+cv/nc^2)

u= c/n(1+ nv/c)/(1+v/nc)

(b) We have , v<<c

v/c<<1 .

so , (1+v/nc )^-1 = (1-v/nc)

Now substituting this , we will get ,

u = c/n(1+nv/c) (1-v/nc)

u≈c/n(1+ nv/c-v/cn)

u≈c/n + v - v/n^2

Hence , it is proved that when v<<c , then speed of the light measured in the laboratory frame is , u = c/n + v -v/n^2 .

Learn more about speed here :

brainly.com/question/13943409

#SPJ4

Disclaimer : incomplete question , here is the complete question .

Question: The motion of a transparent medium influences the speed of light. This effect was first observed by Fizeau in1851. Consider a light beam in water. The water moves with speed v in a horizontal pipe. Assume the light travels in the same direction as the water moves. The speed of light with respect to the water is c / n , where n=1.33 is the index of refraction of water.(a) Use the velocity transformation equation to show that the speed of the light measured in the laboratory frame isu = c/n (1 + nv/c / 1+ v/nc) . (b) show that for v<<c , the expression from part (a) becomes , to a good approximation , u ≈ c/n + v - v/n^2 .

8 0
2 years ago
A charged particle accelerated to a velocity v enters the chamber of a mass spectrometer. The particle's velocity is perpendicul
gladu [14]

Answer:

Circle

Explanation:

When a charged particle is in motion in a region with magnetic field, the particle experiences a force whose magnitude is given by

F=qvB sin \theta

where

q is the charge

v is the velocity of the particle

B is the strength of the magnetic field

\theta is the angle between the directions of v and B

In this problem, the velocity of the particle is perpendicular to the magnetic field, so

\theta=90^{\circ}

and the formula reduces to

F=qvB

Also, the direction of this force is perpendicular to the direction of motion of the particle. This means that as the charge moves in the region of the magnetic field, the force acting on it acts as a centripetal force: therefore, the particle will start moving by unifom circular motion, with constant speed (because the magnetic force does no work on the particle, since it is perpendicular to the direction of motion).

So, the path of the particle will be a circle.

4 0
4 years ago
Name two practical applications of nanotechnology
kicyunya [14]
1.Development in quantum theories
2.Development in quantum computers
3 0
3 years ago
Please answer and explain the equations of how you got the answer
Dima020 [189]

Answer:

a) H=277113.45m

b) t = 142.09 seconds  

Solution

In this question we have given

initial speed, v= 1.7x10^3m/s

angle of projection with ground, α= 55 degree

a) Neglecting air resistance, horizontal component of velocity is given as

V(h)=vcos\alpha............(1)

put value of v and α in equation(1)

V(h)=cos 55\times1.7x10^3m/s

V(h) = 975.08 m/s  

Now, horizontal range is given as

H = V(h) \times t

H = 975.08 \times t

= 975.08t m .... (1)  


b) Time of flight

Vertical component of velocity is given as

V(v)=vsin\alpha............(1)

V(v)=vsin55\times1.7x10^3m/s

V(v) = 1392.5585 m/s  

We know that time to reach at maximum height is given by formula

t=\frac{V(v)}{g}

t= (1392.5585 m/s)/9.8m/s^2

time to reach at maximum height,t = 142.09seconds  

Total time in air 2t = 284.19 seconds.

put value of t in equation (1)

Therefore horizontal range is given as

H=975.08m/s\times284.19s\\H=277113.45m

3 0
3 years ago
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