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Illusion [34]
3 years ago
10

You drop a rock off a bridge. When the rock has fallen 4 m, you drop a second rock. As the two rocks continue to fall, what happ

ens to their velocities?
a. Both increase at the same rate.
b. The velocity of the first rock increases faster than the velocity of the second.
c. The velocity of the second rock increases faster than the velocity of the first.
d. Both velocities stay constant.
Physics
1 answer:
Mashutka [201]3 years ago
4 0

Answer:

option A.

Explanation:

The correct answer is option A.

Two rocks are off a bridge first rock is fallen 4  when the second rock is dropped.

Both the rock is dropped under the effect of acceleration due to gravity so, the rate of change of the velocity for both the rock particle will be the same.

Hence, the first rock will reach ground earlier than the second rock because the rate of change of both the rock is at the same rate.

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When a pitcher is throwing a ball, is he applying positive or negative work to the ball?
Romashka [77]
A.Positive as work=force×distance (assuming that distance is always a constant) the work will always be positive as the force is always positive(this is because force=mass×acceleration where the acceleration is always positive unless the mass is being slowed down)
5 0
3 years ago
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An object is located 5.0 cm from a concave mirror. The focal length is 15.0 cm. What is the image distance? Use the equation att
Fiesta28 [93]

Answer:

-7.5 cm

Explanation:

OK so in the equation they're having you use the variables are:

d_o = 5.0 cm\\\\f = 15.0 cm\\\\d_i = ?

So we simply plug in the variables:

d_i = \frac{d_of}{d_o-f} \\\\d_i = \frac{5.0 * 15.0}{5.0 - 15.0}\\\\d_i = \frac{75}{-10}\\\\d_i = -7.5 cm

6 0
3 years ago
Suppose you exert a force of 180 N tangential to a 0.280-m-radius 75.0-kg grindstone (a solid disk). (a)What torque is exerted?
Iteru [2.4K]

(a) 50.4 N\cdot m

The torque exerted on the solid disk is given by

\tau=Frsin \theta

where

F is the magnitude of the force

r is the radius of the disk

\theta is the angle between F and r

Here we have

F = 180 N

r = 0.280 m

\theta=90^{\circ} (because the force is applied tangentially to the disk)

So the torque is

\tau = (180 N)(0.280 m)(sin 90^{\circ})=50.4 N\cdot m

(b) 17.2 rad/s^2

First of all, we need to calculate the moment of inertia of the disk, which is given by

I=\frac{1}{2}mr^2

where

m = 75.0 kg is the mass of the disk

r = 0.280 m is the radius

Substituting,

I=\frac{1}{2}(75.0)(0.280)^2=2.94 kg m^2

And the angular acceleration can be found by using the equivalent of Newtons' second law for rotational motions:

\tau = I \alpha

where

\tau = 50.4 N \cdot m is the torque exerted

I is the moment of inertia

\alpha is the angular acceleration

Solving for \alpha, we find:

\alpha = \frac{\tau}{I}=\frac{50.4 N \cdot m}{2.94 kg m^2}=17.2 rad/s^2

8 0
3 years ago
What kind of electricity do your socks have when they come out of the drier?
viva [34]
The answer is electrical
5 0
3 years ago
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Which answer is true about an object undergoing projectile motion?
avanturin [10]

Answer:

Select the answer that states:

<em>VX = constant, and ay = -g</em>

Explanation:

In the case of an object undergoing projectile motion, such motion is divided in two analysis. The vertical analysis uses kinematic equations associated with an accelerated motion under the constant acceleration of gravity, and the horizontal analysis is that of a uniform motion at constant velocity.

Therefore the projectile motion uses the velocity in the horizontal (x-direction) as constant. and the vertical motion (associated with the y-axis) a motion with acceleration equal to "g".

Then, the corect answer is the one that states:

"<em>VX = constant, and ay = -g</em>"

8 0
2 years ago
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