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viva [34]
3 years ago
11

kelly belonged to a canoe club that had 18 canoes. they kept their canoes om trailers, each able.to carru 2 wide and 3 high. if

they had enough trailers for all of their canoes, how many trailers did they have?
Mathematics
1 answer:
aleksley [76]3 years ago
3 0
So 6 canoes per trailer, there are 18 canoes total. How many trailes are needed to fit all the canoes.

3 trailers.
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To evaluate the effect of a treatment, a sample is obtained from a population, with a mean of u = 30, and the treatment is admin
Murrr4er [49]

Answer:

a) t=\frac{31.3-30}{\frac{3}{\sqrt{16}}}=1.733  

p_v =2*P(t_{15}>1.733)=0.104  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the we don't have a significant effect for the new treatment at 5% of significance.  

b) t=\frac{31.3-30}{\frac{3}{\sqrt{36}}}=2.6  

p_v =2*P(t_{15}>2.6)=0.0201  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the we have a significant effect for the new treatment at 5% of significance.  

c) When we increase the sample size we increse the probability of rejection of the null hypothesis since the z score tend to increase when the sample size increase.

Step-by-step explanation:

Data given and notation  

Part a: If the sample consists of n=16 individuals, are the data sufficient to conclude that the treatment has a significant effect using a two-tailed test with alpha = 0.05.

\bar X=31.3 represent the sample mean  

s=3 represent the sample standard deviation  

n=16 sample size  

\mu_o =30 represent the value that we want to test  

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is different from 30, the system of hypothesis are :  

Null hypothesis:\mu = 30  

Alternative hypothesis:\mu \neq 30  

Since we don't know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{31.3-30}{\frac{3}{\sqrt{16}}}=1.733  

P-value  

First w eneed to find the degrees of freedom given by:

df=n-1=16-1 =15

Since is a two-sided test the p value would given by:  

p_v =2*P(t_{15}>1.733)=0.104  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the we don't have a significant effect for the new treatment at 5% of significance.  

Part b: If the sample consists of n=36 individuals, are the data sufficient to conclude that the treatment has a significant effect using a two-tailed test with alpha = 0.05.

Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{31.3-30}{\frac{3}{\sqrt{36}}}=2.6  

P-value  

First w eneed to find the degrees of freedom given by:

df=n-1=16-1 =15

Since is a two-sided test the p value would given by:  

p_v =2*P(t_{15}>2.6)=0.0201  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the we have a significant effect for the new treatment at 5% of significance.  

Part c; Comparing your answer for parts a and b, how does the size of the sample influence the outcome of a hypothesis test

When we increase the sample size we increse the probability of rejection of the null hypothesis since the z score tend to increase when the sample size increase.

5 0
4 years ago
Help me <br> -2= X^3-4x^2+x+6
andrezito [222]

Answer

The answer/ soulution = eirwyntvfeimvwyfwvmi

Step-by-step explanation:

8 0
3 years ago
City A: {2, 2.5, 4, 4.5, 3, 2.5} City B: {6, 4, 1.5, 3.5, 2, 4} (c) What is the median for each city? Show your work. City A: Ci
Anit [1.1K]

Answer:

to find the median you have to put the set in order and find the middle number (ex: 1,2,3,4,5,6,7,8,9 the median of this would be 5)

Step-by-step explanation:

City A: 2,2.5,2.5,3,4,4.5

The median has 2 number so you'd add them up and divide by 2.

2.5 + 3 = 5.5

5.5/2= 2.75

i dont know if you need it as a fraction

City B: 1.5,2,3.5,4,4,6

3.5+4 = 7.5

7.5/2 = 3.75

Median for city A: 2.75

Median for city B: 3.75

3 0
3 years ago
Four gallons of paint are used to paint 25 chairs. if each chair used the same amount of paint how many gallons are used to pain
timofeeve [1]
Each chair uses 0.16 gallons to be painted. I think this number lies between 0 and 1.
4 0
3 years ago
Wrestling wins<br> 5 7 13 24 16 22 13 7 6
emmasim [6.3K]
5, 6, 7, 7, 13, 13, 16, 22, 24
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Median
Median is 13
3 0
3 years ago
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