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sesenic [268]
2 years ago
15

A student delivered 17.06 mL (V1) of 7.16 % stock solution (M1) using a graduated pipette into a 50.00 mL (V2) volumetric flask.

Distilled water was added to the flask to the graduation mark and mixed well.
Using the dilution equation (provided below), calculate the concentration of the diluted solution.

(M1)(V1) = (M2)(V2)
Chemistry
1 answer:
Nikolay [14]2 years ago
4 0

The concentration of the diluted solution will be 2.44%.

<h3>Dilution problem</h3>

From the equation of dilution:

(M1)(V1) = (M2)(V2).

where M1 = concentration before dilution, M2 = concentration after dilution, V1 = volume before dilution, and V2 = volume after dilution.

In this case:

V1 = 17.06 mL

V2 = 50.00 mL

M1 = 7.16%

M2 = ?

M2 = (M1)(V1)/(V2)

        = 7.16 x 17.06/50

               = 2.44%

Thus, the concentration of the diluted solution is 2.44%.

More on dilution can be found here: brainly.com/question/21323871

#SPJ1

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Question 15 (1 point)
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Atoms are electrically neutral because the number of protons, which carry a 1+ charge, in the nucleus of an atom is equal to the number of electrons, which carry a 1- charge, in the atom. The result is that the total positive charge of the protons cancels out the total negative charge of the electrons so that the net charge of the atom is zero. Most atoms, however, can either gain or lose electrons; when they do so, the number of electrons becomes different from the number of protons in the nucleus. The resulting charged species is called an ion.

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When a neutral atom loses one or more electrons, the total number of electrons decreases while the number of protons in the nucleus remains the same. The result is that the atom becomes a cation—an ion with a net positive charge.

The opposite process can also occur. When a neutral atom gains one or more electrons, the number of electrons increases while the number of protons in the nucleus remains the same. The result is that the atom becomes an anion—an ion with a net negative charge. We can illustrate this by examining some very simple cations and anions, those formed when a single hydrogen atom loses or gains an electron.

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A hydrogen cation, a hydrogen atom, and a hydrogen anion.

A hydrogen cation, a hydrogen atom, and a hydrogen anion.

Classification cation neutral atom anion

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No. of electrons 000 111 222

Net charge 111++plus 000 111-−minus

If a neutral hydrogen atom ( \text{H}Hstart text, H, end text, center) loses an electron, it becomes a hydrogen cation ( \text{H}^+H  

+

start text, H, end text, start superscript, plus, end superscript, left). Conversely, if the neutral \text{H}Hstart text, H, end text atom gains an electron, it becomes a hydrogen anion ( \text{H}^-H  

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start text, H, end text, start superscript, minus, end superscript, right), also known as a hydride ion. Image credit: adapted from Boundless Learning, CC BY-SA 4.0.

In the center column, we have a diagram of a single, neutral hydrogen atom. It contains one proton and one electron; thus, its net charge is zero. If hydrogen loses its electron, it forms the cation \text{H}^+H  

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start text, H, end text, start superscript, plus, end superscript (left column). The \text{H}^+H  

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start text, H, end text, start superscript, plus, end superscript cation has a net charge of 1+ from the one proton in the nucleus since there are no electrons to cancel out the positive charge. If neutral hydrogen gains an electron, it forms the anion \text{H}^-H  

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start text, H, end text, start superscript, minus, end superscript (right column). The \text{H}^-H  

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start text, H, end text, start superscript, minus, end superscript anion has a net charge of 1- because it has one extra electron compared to the total number of protons.

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