Question

A student delivered 17.06 mL (V1) of 7.16 % stock solution (M1) using a graduated pipette into a 50.00 mL (V2) volumetric flask. Distilled water was added to the flask to the graduation mark and mixed well.
Using the dilution equation (provided below), calculate the concentration of the diluted solution.

(M1)(V1) = (M2)(V2)

Answer 1

The concentration of the diluted solution will be 2.44%.

Dilution problem

From the equation of dilution:

(M1)(V1) = (M2)(V2).

where M1 = concentration before dilution, M2 = concentration after dilution, V1 = volume before dilution, and V2 = volume after dilution.

In this case:

V1 = 17.06 mL

V2 = 50.00 mL

M1 = 7.16%

M2 = ?

M2 = (M1)(V1)/(V2)

        = 7.16 x 17.06/50

               = 2.44%

Thus, the concentration of the diluted solution is 2.44%.

More on dilution can be found here: brainly.com/question/21323871

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