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GrogVix [38]
3 years ago
8

How many moles are in 82 g of water?

Chemistry
1 answer:
guajiro [1.7K]3 years ago
4 0
Take 82 grams and divide it by the gfm of water which is 18 g/mole...(82g)/(18.0g/mole)=4.555 -> the answer is 4.6 moles
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Using the van der Waals equation, the pressure in a 22.4 L vessel containing 1.00 mol of neon gas at 100 °C is ________ atm. (a
svetoff [14.1K]

Answer:

The answer to your question is        P = 1.357 atm

Explanation:

Data

Volume = 22.4 L

1 mol

temperature = 100°C

a = 0.211 L² atm

b = 0.0171 L/mol

R = 0.082 atmL/mol°K

Convert temperature to °K

Temperature = 100 + 273

                      = 373°K

Formula

               (P + \frac{a}{v^{2}} )(v - b) = RT

Substitution

               (P + \frac{0.211}{22.4})(22.4 - 0.0171) = (0.082)(373)

Simplify

               (P + 0.0094)(22.3829) = 30.586

Solve for P

                           P + 0.0094 = \frac{30.586}{22.3829}

                           P + 0.0094 = 1.366

                                 P = 1.336 - 0.0094

                                P = 1.357 atm

7 0
4 years ago
Match the following vocabulary words with their definitions.
omeli [17]
1. condensation
2. evaporation
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6 0
3 years ago
Read 2 more answers
What can you tell by tracking oxidation numbers?
Alla [95]

<u>Answer</u>:

By tracking oxidation numbers we can identify the number electron in the atom

<u>Explanation</u>:

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7 0
3 years ago
An aqueous solution of calcium hydroxide is standardized by titration with a 0.112 M solution of hydrobromic acid. If 15.2 mL of
TiliK225 [7]

Answer:

0.0457 M

Explanation:

The reaction that takes place is:

  • 2HBr + Ca(OH)₂ → CaBr₂ + 2H₂O

First we<u> calculate how many moles of acid reacted</u>, using the <em>HBr solution's concentration and volume</em>:

  • Molarity = Moles / Volume
  • Molarity * Volume = Moles
  • 0.112 M * 12.4 mL = 1.389 mmol HBr

Now we <u>convert HBr moles to Ca(OH)₂ moles</u>, using the stoichiometric ratio:

  • 1.389 mmol HBr * \frac{1mmolCa(OH)_{2}}{2mmolHBr} = 0.6944 mmol Ca(OH)₂

Finally we <u>calculate the molarity of the Ca(OH)₂ solution</u>, using the <em>given volume and calculated moles</em>:

  • 0.6944 mmol Ca(OH)₂ / 15.2 mL = 0.0457 M
7 0
3 years ago
The rate law for the decomposition of phosphine (PH3) is below. It takes 120. s for 1.00 M PH3 to decrease to 0.250 M. How much
Lubov Fominskaja [6]

Answer: 588.8 seconds

Explanation:

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Therefore,

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Cross multiply:

0.75*x = 120*3.68

x = 120*3.68/0.75

x = 588.8 seconds

8 0
4 years ago
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