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Vedmedyk [2.9K]
3 years ago
6

Based on your knowledge of chemical equations, what do you know for sure

Chemistry
1 answer:
Artyom0805 [142]3 years ago
5 0
Pretty sure it shows a chemical reaction
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Molar mass c3h8
maksim [4K]

Answer:

1. 44.11 g

2. 36.03 g

3. 8.08 g

4. 81.7%

5. 18.3%

Explanation:

1. 12.01+12.01+12.01+1.01+1.01+1.01+1.01+1.01+1.01+1.01+1.01=44.11

2. 12.01×3= 36.03

3. 1.01×8= 8.08

4.(36.03/44.11)×100= 81.7%

5. (8.08/44.11)×100= 18.3%

8 0
2 years ago
I need help on deciding which one i should get
alekssr [168]

Answer:

I would say the purple one!

Explanation:

4 0
2 years ago
Read 2 more answers
Commercial grade fuming nitric acid contains about 90.0% HNO3 by mass with a density of 1.50 g/mL, calculate the molarity of the
andrew-mc [135]

Answer:

Since molarity is defined as moles of solute per liter of solution, we need to find the number of moles of nitric acid, and the volume of solution.

molar mass of nitric acid (HNO3) = 1 + 14 + (3x16) = 15 + 48 = 63 g/mole

1.50 g/ml x 1000 ml = 1500 g/liter

1500 g/liter x 0.90 = 1350 g/liter of pure HNO3 (the 0.9 is to correct for the fact that it is 90% pure)

1350 g/liter x 1 mole/63 g = 21.43 moles/liter = 21 Molar HNO3

= 21 Molar of HNO3

8 0
2 years ago
Read 2 more answers
The compound magnesium iodide is a strong electrolyte write the reaction when solid magnesium iodide is put into water
mestny [16]
  The  reaction  for magnesium  iodide  when put into water  is  as below

 MgI2(s) →  Mg^2+(aq)   + 2I^-(aq)

when  magnesium iodide  but into water it dissociate/ ionize  completely  into  Mg^2+  and  2l^-   ions. Magnesium iodide dissociate/ionize  completely because  magnesium  iodide  is a strong electrolyte  which  dissociate/ ionize  completely into their ions  when it is put into   water .
7 0
3 years ago
Suppose that in an ionic compound, "m" represents a metal that could form more than one type of ion. in the formula mf2 , the ch
geniusboy [140]
F (Fluorine) is in column (group/family) VIIA, or the "halogens". When you see the halogens (Fluorine, Chlorine, Bromine, and Iodine) in combination with a metal, each halogen atom present will carry a -1 charge. We can see that the atom has no charge, so the metal must cancel out the negative charges brought by the two fluorine atoms.
(Charge on m) + 2*(charge on fluorine) = 0
(Charge on m) + 2*(-1) = 0
(Charge on m) - 2 = 0
Charge on m ion = +2
3 0
3 years ago
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