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nikklg [1K]
3 years ago
6

A 3.50 g sugar cube (sucrose: C12H22O11) is dissolved in a 350 mL teapot containing 80∘ C water (density of water at 80∘ C= 0.97

5 g/mL). What is the molality of the sugar solution?
Chemistry
2 answers:
KIM [24]3 years ago
6 0

Answer: 0.04893mole/kg

Explanation:

Molality is defined as the mole of solute per kilogram of the solvent.

Sugar is the solute while water is the solvent.

Molar mass of sugar =

1*12+1*22+11*16

12+22+176=210g/mol.

Mole of solute= reacting mass /molar mass

Reacting mass 3.50g and molar mass 210g/mol

Mole= 3.50/210=0.0167moles.

For solvent

Density=mass/volume

Mass= density *volume

0.975*350

341.25g

Converting gram back to kilogram

341.25/1000= 0.34125kg

Molality =0.0167/0.34125

=0.04893mole/kg

mestny [16]3 years ago
6 0

Answer:

Molality is 0.03 m

Explanation:

Molality indicates the moles of solute that are contained in 1000g of solvent.

We have solvent volume and density, so let's find out the mass:

Solvent density = Solvent mass / Solvent volume

Solvent density . Solvent volume = Solvent mass → 0.975 g/mL . 350 mL

Solvent mass = 341.25g

Now we need the moles of solute → mass of solute / molar mass

3.50 g / 342 g/mol = 0.0102 moles

So finally we can make a rule of three:

341.25 g of solute contain 0.0102 moles of solute

1000 g of solute, may contain (1000 . 0.0102) / 341.25 = 0.03 m

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aliya0001 [1]

Answer:

2x+3y=-6

4x+3y=12

3x-y=5

5x+3y=1

Explanation:

standard form: ax + by = C

4 0
3 years ago
The radioactivity due to carbon-14 measured in a piece of a wooden casket from an ancient burial site was found to produce 20 co
bekas [8.4K]

Answer:

17202.6 years

Explanation:

Activity of the living sample (Ao) = 160 counts per minute

Activity of the wood sample (A) = 20 counts per minute

Half life of carbon-14 = 5730 years

t= age of the artifact

From;

0.693/t1/2= 2.303/t log Ao/A

Then;

0.693/ 5730= 2.303/t log Ao/A

Substituting values;

0.693/5730= 2.303/t log (160/20)

Then we obtain;

1.209×10^-4 = 2.0798/t

t= 2.0798/1.209×10^-4

Thus;

t= 17202.6 years

Therefore the artifact is 17202.6 years old.

3 0
3 years ago
How much (Q) heat is needed to melt 35 g of iodine? Hf = 61.7 J/g.
aev [14]

Taking into account the definition of calorimetry and latent heat, a heat of 2159.5 J is needed to melt 35 g of iodine.

<h3>Calorimetry</h3>

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

<h3>Latent heat</h3>

Latent heat is defined as the energy required by a quantity of substance to change state.

When this change consists of changing from a solid to a liquid phase, it is called heat of fusion and when the change occurs from a liquid to a gaseous state, it is called heat of vaporization.

The heat Q that is necessary to provide for a mass m of a certain substance to change phase is equal to

Q = m×L

where L is called the latent heat of the substance and depends on the type of phase change.

<h3>Heat needed to melt iodine</h3>

In this case, you know:

  • m= 35 g
  • L=61.7 \frac{J}{g}

Replacing in the definition of latent heat:

Q= 35 g× 61.7 \frac{J}{g}

Solving:

<u><em>Q=2159.5 J</em></u>

Finally, a heat of 2159.5 J is needed to melt 35 g of iodine.

Learn more about calorimetry:

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#SPJ1

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2 years ago
What is the role of roughages in the balanced diet​
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Roughage, also known as Dietary fibre is thought to play an important role in digestive health, heart health, preventing Type 2 diabetes, as well as maintaining energy levels.
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3 years ago
lighting a match results in light and heat since energy was not created by the match what transformation took place
Contact [7]

It is a chemical reaction


7 0
3 years ago
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