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3 years ago

____ is the process in which energy is released as the nuclei of small atoms combine to form a larger nucleus

1 answer:

8 0

It is called fusion. It is the process taking place on our sun, as two hydrogen atoms fuse together to form a helium atom and give off a small amount of energy <span>while losing some mass.</span>

Hope this satisfies your query! Have a good one :)

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Abdid is an astronomer who has been observing objects that orbit the Sun in the asteroid belt. He finds a previously undiscovere

Elza [17]

Since it is round and it is the asteroid belt it is most likely that he found a dwarf planet

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2 years ago

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Round the nearseat whole number how many neutrons on average are in atom of osmium?

Anettt [7]

Answer:

jdjdjdhjxjxjchxjxjkxjxjxhxnxkjcjcjcj

Explanation:

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2 years ago

The burning of a sample of propane generated 1 04.6 kJ of heat. All of this heat was used to heat 500.0 g of water that had an i

Paul [167]

Answer: 70.0°C

Explanation:

Quantity of heat = Mass * Specific heat * Change in temperature

Quantity of heat = 104.6 KJ

Mass = 500.0 g

Specific heat of water is 4.18 J/g°C

Change in temperature assuming final temperature is x = x - 20

Units should be in grams and joules:

104,600 = 500 * 4.18 * (x - 20)

104,600 = 2,090 * (x - 20)

x - 20 = 104,600/2,090

x = 104,600/2,090 + 20

x = 69.8

= 70.0°C

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2 years ago

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slamgirl [31]

I will help you with answering this question.

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2 years ago

How many hours will it take for the concentration of methyl isonitrile to drop to 15.0 % of its initial value?

SpyIntel [72]

Answer:

The concentration of methyl isonitrile will become 15% of the initial value after 10.31 hrs.

Explanation:

As the data the rate constant is not given in this description, However from observing the complete question the rate constant is given as a rate constant of 5.11x10-5s-1 at 472k .

Now the ratio of two concentrations is given as

$ln (\frac{C}{C_0})=-kt$

Here C/C_0 is the ratio of concentration which is given as 15% or 0.15.

k is the rate constant which is given as $5.11 \times 10^{-5} \, s^{-1}$

So time t is given as

$ln (\frac{C}{C_0})=-kt\\ln(0.15)=-5.11 \times 10^{-5} \times t\\t=\frac{ln(0.15)}{-5.11 \times 10^{-5} }\\t=37125.6 s\\t=37125.6/3600 \\t= 10.31 \, hrs$

So the concentration will become 15% of the initial value after 10.31 hrs.

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2 years ago

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