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Reil [10]
3 years ago
7

If the concentration of a sugar solution is lower outside the cell than inside the cell which will happen by osmosis?. A.Sugar w

ill move into the cell.. B.Sugar will move out of the cell.. C.Water will move into the cell.. D.Water will move out of the cell.
Chemistry
1 answer:
lys-0071 [83]3 years ago
3 0

Answer: option C.Water will move into the cell

Explanation:

1) Start by analyzing what the statement means in terms of relative concentrations:

------------------------ | inside the cell ------------ | outside the cell |

sugar --------------- | higher ----------------------- | lower ------------- |

water -------------- | lower ------------------------- | higher ------------ |

2) Osmosis is the process where a barrier (the celll membrane) permits the pass of some component and not others.

The component that can pass is that whose particles are smaller. Sugar molecules (the solute) are bigger than water molecules (the solvent), so sugar molecules cannot pass the cell membrane. Only water can.

3) The driviing force for the motion of water molecules is called diffusion. The diffusion occurs from higher concentrations to lower concentrations.

Hence, the water molecules will from outside the outiside the cell, where they have the greater concentration, toward the inside of the cell, where water hasa the lower concentration.

As result, the water will move into the cell, which is the option C.

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When nitrogen dioxide (NO2) from car exhaust combines with water in the air, it forms nitric acid (HNO3), which causes acid rain
yKpoI14uk [10]

<u>Answer:</u>

<u>For a:</u> The number of molecules of nitrogen dioxide is 4.52\times 10^{23}

<u>For b:</u> The mass of nitric acid formed is 54.81 grams

<u>For c:</u> The mass of nitric acid formed is 206 grams

<u>Explanation:</u>

The given chemical reaction follows:

3NO_2(g)+H_2O(l)\rightarrow 2HNO_3(aq.)+NO(g)

  • <u>For a:</u>

By Stoichiometry of the reaction:

1 mole of water reacts with 3 moles of nitrogen dioxide

So, 0.250 moles of water will react with \frac{3}{1}\times 0.250=0.75mol of nitrogen dioxide

According to mole concept:

1 mole of a compound contains 6.022\times 10^{23} number of molecules.

So, 0.75 moles of nitrogen dioxide will contain 0.75\times 6.022\times 10^{23}=4.52\times 10^{23} number of molecules

Hence, the number of molecules of nitrogen dioxide is 4.52\times 10^{23}

  • <u>For b:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

Given mass of nitrogen dioxide = 60.0 g

Molar mass of nitrogen dioxide = 46 g/mol

Putting values in equation 1, we get:

\text{Moles of nitrogen dioxide}=\frac{60.0g}{46g/mol}=1.304mol

By Stoichiometry of the reaction:

3 moles of nitrogen dioxide produces 2 mole of nitric acid

So, 1.304 moles of nitrogen dioxide will produce = \frac{2}{3}\times 1.304=0.870 moles of nitric acid

Now, calculating the mass of nitric acid from equation 1, we get:

Molar mass of nitric acid = 63 g/mol

Moles of nitric acid = 0.870 moles

Putting values in equation 1, we get:

0.870mol=\frac{\text{Mass of nitric acid}}{63g/mol}\\\\\text{Mass of nitric acid}=(0.870mol\times 63g/mol)=54.81g

Hence, the mass of nitric acid formed is 54.81 grams

  • <u>For c:</u>
  • <u>For nitrogen dioxide:</u>

Given mass of nitrogen dioxide = 225 g

Molar mass of nitrogen dioxide = 46 g/mol

Putting values in equation 1, we get:

\text{Moles of nitrogen dioxide}=\frac{225g}{46g/mol}=4.90mol

  • <u>For water:</u>

Given mass of water = 55.2 g

Molar mass of water = 18 g/mol

Putting values in equation 1, we get:

\text{Moles of water}=\frac{55.2g}{18g/mol}=3.06mol

By Stoichiometry of the reaction:

3 moles of nitrogen dioxide reacts with 1 mole of water

So, 4.90 moles of nitrogen dioxide will react with = \frac{1}{3}\times 4.90=1.63mol of water

As, given amount of water is more than the required amount. So, it is considered as an excess reagent.

Thus, nitrogen dioxide is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

3 mole of nitrogen dioxide produces 2 moles of nitric acid

So, 4.90 moles of nitrogen dioxide will produce \frac{2}{3}\times 4.90=3.27mol of nitric acid

Now, calculating the mass of nitric acid from equation 1, we get:

Molar mass of nitric acid = 63 g/mol

Moles of nitric acid = 3.27 moles

Putting values in equation 1, we get:

3.27mol=\frac{\text{Mass of nitric acid}}{63g/mol}\\\\\text{Mass of nitric acid}=(3.27mol\times 63g/mol)=206g

Hence, the mass of nitric acid formed is 206 grams

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How many sulfur atoms would be present in 41.8 moles of sulfur?
Montano1993 [528]

Answer:

2.51 x 10*25 atoms

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4 years ago
If the temperature of a gas confined to such a cylinder is raised from 287°C to 587°C, what is the ratio of the initial volume t
jenyasd209 [6]

Answer:

1 : 2

Explanation:

From the question given, we obtained the following information:

T1 = 287°C = 287 +273 = 560K

T1 = 587°C = 587 +273 =860K

V1 = V

V2 =?

V1 /T1 = V2 /T2

V/560 = V2/860

Cross multiply

V2 x 560 = 860 x V

Divide both side by 560

V2 = (860 x V) / 560

V2 = 1.54V = 2V

The ratio of initial to final volume =

V1 : V2

= V : 2V

= 1 : 2

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What is the half-life of a radioisotope?
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<span>A.The amount of time it takes for half of the material to decay</span>
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3 years ago
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