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Ivenika [448]
3 years ago
13

What is the factor that affects how easily an electron can be removed from an atom?

Chemistry
1 answer:
alexgriva [62]3 years ago
8 0
I think the correct answer among the choices listed above is option D. It is the structure of the atom that is the <span>factor that affects how easily an electron can be removed from an atom. This is because having a stronger structure would mean that electrons have a strong attraction to the atom and it would be harder to remove the electrons.</span>
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maria [59]

Answer:

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Explanation:

3.2 gl

4 0
3 years ago
A sample of O2(g) is placed in an otherwise empty, rigid container at 4224 K at an initial pressure of 4.97 atm, where it decomp
frutty [35]

Answer:

The value of K_p at 4224 K is 314.23.

Explanation:

O_2(g)\rightleftharpoons 2O(g)

Initially

4.97 atm            0

At equilibrium

4.97 - p               2p

At initial stage, the partial pressure of oxygen gas = =4.97 atm

At equilibrium, the partial pressure of oxygen gas = p_{O_2}=0.28 atm

So, 4.97 - p = 0.28 atm

p = 4.69 atm

At equilibrium, the partial pressure of O gas = p_{O}=2p=2\times 4.69 atm=9.38 atm

The expression of K_p is given as :

K_p=\frac{(p_{O})^2}{(p_{O_2})}

K_p=\frac{(9.38 atm)^2}{0.28 atm}=314.23

The value of K_p at 4224 K is 314.23.

5 0
3 years ago
PLEASE HELP, DUE AT 12:00
elena55 [62]

Answer:

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Explanation:

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7 0
3 years ago
2 The substance has a mass of 0.50 kg.
katen-ka-za [31]

Answer:

68000J/kg

Explanation:

Given parameters:

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Unknown:

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Solution:

The specific latent heat is usually involve in phase changes;

  H  = mL

H is the quantity of heat supplied

m is the mass

L is the specific latent heat

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     34000 = 0.5 x L

         L  = \frac{34000}{0.5}   = 68000J/kg

5 0
3 years ago
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vladimir1956 [14]
The answer is RADICAL
8 0
3 years ago
Read 2 more answers
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