Answer:
12
Explanation:
You will need a chemical equation with masses and molar masses, so let’s gather all the information in one place.
: 258.21 18.02
KAl(SO₄)₂·xH₂O ⟶ KAl(SO₄)₂ + xH₂O
Mass/g: 4.74 2.16
Step 1. Calculate the mass of the KAl(SO₄)₂.
Mass = 4.74 g – 2.16 g = 2.58 g.
Step 2. Calculate the moles of each product.


Step 3. Calculate the molar ratio of the two products.

1 mol of KAl(SO₄)₂ combines with 12 mol H₂O, so x = 12.
It would most likely be acid rain
Answer:
Bismuth
Explanation:
In order to do this problem, we must use a periodic table. The molar mass is numerically equivalent to the atomic mass, which is provided for each element on the periodic table.
Xenon (Xe) has an atomic mass of 131.29 amu, or 131.29 g/mol.
Bismuth (Bi) has an atomic mass of 208.98 amu, or 208.98 g/mol.
Rhodium (Rh) has an atomic mass of 102.91 amu, or 102.91 g/mol.
Antimony (Sb) has an atomic mass of 121.76 amu, or 121.76 g/mol.
Thus, the answer is Bismuth because 208.98 is the largest.
Hope this helps!
Answer: The objects that are luminous are a lamp and a computer screen
Explanation: This is because these two objects shine or glow with light.
Given, mass of isotope 1 = 39.06 amu
% abundance of isotope 1 = 10.00%
mass of isotope 2 = 42.14 amu
% abundance of isotope 2 = 90.00%
Average atomic mass
= [ (mass of isotope 1 x % abundance of isotope 1 ) + (mass of isotope 2 x % abundance of isotope 2 ) ]/ 100
= [(39.06 x 10) + (42.14 x 90)]/100
= (390.6 + 3792.6) / 100
= 4183.2/100
= 41.8 (to the nearest tenth)
Therefore, the weighted atomic mass of element Q is 41.8 amu.