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Sladkaya [172]
3 years ago
13

Consider the balanced chemical reaction below. When the reaction was carried out, the calculated theoretical yield for carbon di

oxide was 93.7 grams, but the measured yield was 88.3 grams. What is the percent yield?
Fe2O3 + 3CO --> 2Fe + 3CO2
Chemistry
2 answers:
bekas [8.4K]3 years ago
8 0

Answer:94.23

Explanation:

Hope it helps

Arada [10]3 years ago
3 0

The percent yield represents that the efficiency of a reaction.

It represents how much times we have achieved the target yield from a particular reaction

The relation between theoretical yield, measured yield and percent yield is

percent yield = \frac{measuredyieldX100}{theoreticalyield}

for the given reaction

percent yield = \frac{88.3X100}{93.7}=94.23%

Answer: 94.23%

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If the distance between London and New York is 3600 miles, how long would you
Tju [1.3M]

Answer:

3 hours

Explanation:

s=d/t

1200=3600/t

3600/1200=t

t=3

3 0
3 years ago
What is the weight of:
Dafna11 [192]

Answer:

Oxygen = 15.999 g/mol

Iron = 3 × 55.845 = 167.535 g/mol

CaCO3 = 20 × 100.0869 = 2001.738 g/mol

8 0
3 years ago
A lab technician mixes a 0.730 M solution of sodium bromide (NaBr) and water. The volume of the solution is 135 milliliters.
Ivenika [448]

Answer:

We need 10.14 grams of sodium bromide to make a 0.730 M solution

Explanation:

Step 1: Data given

Molarity of the sodium bromide (NaBr) = 0.730 M

Volume of the sodium bromide solution = 135 mL = 0.135 L

Molar mass sodium bromide (NaBr) = 102.89 g/mol

Step 2: Calculate moles NaBr

Moles NaBr = Molarity NaBr * volume NaBr

Moles NaBr = 0.730 M * 0.135 L

Moles NaBr = 0.09855 moles

Step 3: Calculate mass of NaBr

Mass NaBr = 0.09855 moles * 102.89 g/mol

Mass NaBr = 10.14 grams

We need 10.14 grams of sodium bromide to make a 0.730 M solution

3 0
3 years ago
Read 2 more answers
Consider the following system at equilibrium:
alexgriva [62]

Answer:

A - Increase (R), Decrease (P), Decrease(q), Triple both (Q) and (R)

B - Increase(P), Increase(q), Decrease (R)

C - Triple (P) and reduce (q) to one third

Explanation:

<em>According to Le Chatelier principle, when a system is in equilibrium and one of the constraints that affect the rate of reaction is applied, the equilibrium will shift so as to annul the effects of the constraint.</em>

P and Q are reactants, an increase in either or both without an equally measurable increase in R (a product) will shift the equilibrium to the right. Also, any decrease in R without a corresponding decrease in either or both of P and Q will shift the equilibrium to the right. Hence, Increase(P), Increase(q), and Decrease (R) will shift the equilibrium to the right.

In the same vein, any increase in R without a corresponding increase in P and Q will shift the equilibrium to the left. The same goes for any decrease in either or both of P and Q without a counter-decrease in R will shift the equilibrium to the left. Hence, Increase (R), Decrease (P), Decrease(q), and Triple both (Q) and (R) will shift the equilibrium to the left.

Any increase or decrease in P with a commensurable decrease or increase in Q (or vice versa) with R remaining constant will create no shift in the equilibrium. Hence, Triple (P) and reduce (q) to one third will create no shift in the equilibrium.

6 0
3 years ago
In water, hydrogen bonds are best described as _____.
Elina [12.6K]

Answer: Option D) covalent bonds between water molecules

In water, hydrogen bonds are best described as covalent bonds between water molecules

Explanation:

The hydrogen bonds between water molecules are covalent bonds because they are formed when oxygen attract the lone electron in hydrogen, thus resulting in the formation of a partially negative charge on the oxygen atom and a partially positive charge on two hydrogen atoms

Thus, the sharing of electrons between oxygen and hydrogen atoms is responsible for the covalent bonds between water molecules

7 0
3 years ago
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